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Leto [7]
3 years ago
7

Need help not sure what to do

Mathematics
1 answer:
Rama09 [41]3 years ago
7 0

5a)

2x + 94 = 7x + 49 (vertical angles are equal)

2x - 7x = -94 + 49

-5x = -45

x = 9

Answer

9

5b)

4y + 7x + 49 = 180 (supplementary angles, sum = 180)

4y + 7(9) + 49 = 180

4y + 112 = 180

4y = 68

y = 17

Answer

17

6)

x = 6x - 290 (vertical angles are equal)

-5x = -290

  x = 58

Answer

58


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The Management of a private investment club has a fund of $200,000 earmarked for investment in stocks. To arrive at an acceptabl
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Answer:

In order to obtain a return of 9% per year, we need to invest $133,333.333 in low risk investments, $0 in mid risk investment and $66,666.666 in high risk investment.

Step-by-step explanation:

2/3 of the $200,000 for investment should go to low risk, and the other third to mid risk and high risk. Lets call X the amount that goes into high risk, then the amount that goes to mid risk is 200,000/3 - X.

If we want a 9% of return for the total investment, then we should end with $200,000 * 1.09 = $218,000. We can compute what money we expect to end the year with in terms of X and then obtain the value of X.

We end the year with

200,000 * 1.06 * 2/3 + (200,000/3 - X) * 1.09 + X * 1.15 = 214000 + X * (1.15 - 1.09) = 214000 + X * 0.06

Since we want this amount to be equal to 218000, then

214000+X * 0.06 = 218000

X*0.06 = 218000-214000 = 4000

X = 4000/0.06 = 66,666.666 = 200,000/3

Thus, we are not investing in the mid risk category.

In order to obtain a return of 9% per year, we need to invest $200,000/3 = $133,333.333 in low risk investments, $0 in mid risk investment and $66,666.666 in high risk investment.

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A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What
GalinKa [24]

Answer:

(1) The slope of the line segment AB is 1.\bar 3

(2) The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is (5, 7)

(4) The slope of a line perpendicular to the line AB is-0.75

Step-by-step explanation:

The coordinates of the line segment AB are;

A(2, 3) and B(8, 11)

(1) The slope of a line segment is given by the following equation;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where;

(x₁, y₁) and (x₂, y₂) are two points on the line segment

Therefore;

The slope, m, of the line segment AB is given as follows;

A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)

Slope, \, m_{AB} =\dfrac{11-3}{8-2} = \dfrac{8}{6}  = 1 \frac{1}{3} = 1.\bar3

The slope of the line segment AB = 1.\bar 3

(2) The length, l, of the line segment AB is given by the following equation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Therefore, we have;

l_{AB} = \sqrt{\left (11-3  \right )^{2}+\left (8-2  \right )^{2}} = \sqrt{64 +36} = 10

The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is given as follows;

Midpoint, M = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )

Therefore;

Midpoint, M_{AB} = \left (\dfrac{2 + 8}{2} , \ \dfrac{3 + 11}{2} \right ) = (5, \ 7)

The coordinates of the midpoint of AB is (5, 7)

(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;

m_1 = -\dfrac{1}{m_2}

Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1.\bar 3 is given as follows;

m_1 = -\left (\dfrac{1}{\frac{4}{3} } \right ) = -\dfrac{3}{4}  = -0.75

The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.

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