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Paha777 [63]
4 years ago
13

To get snacks for a class trip, Clare went to the "bulk"

Mathematics
1 answer:
Galina-37 [17]4 years ago
7 0

Answer:6x+9y=75

Step-by-step explanation:

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What can you say about the y-values of the two functions f(x)=3^(x)-3 g(x)=7x^2-3
Mice21 [21]

Answer: g(x) has the smallest possible y-value of -3

<u>Step-by-step explanation:</u>

f(x) = 3ˣ - 3   <em>This is an exponential graph shifted down three units. So, it has an asymptote at y = -3, which means it approaches -3 but does not touch it.</em>

Range: y > 3   (-3, ∞)

   g(x) = 7x² - 3  

⇒ g(x) = 7(x - 0)² - 3   <em>This is a parabola with vertex at (0, -3) </em>

Range: y ≥ 3   [-3, ∞)



5 0
3 years ago
Read 2 more answers
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Leya [2.2K]
The answer is A . Linear
7 0
4 years ago
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Find the area and perimeter of triangle ABF with F(-3,0), A(1,3), and B(7,-5)
lions [1.4K]

Answer:

Step-by-step explanation:

The area would be 25 square centimeter

8 0
3 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
Expression for two years older than Marjorie
Roman55 [17]
2 years older then Marjorie.....m = Marjorie

m + 2 <== ur expression
6 0
4 years ago
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