20% decrease should be the answer
:) Well, I dunno about anyone else but this question makes my head spin!
Answer:
The length of the four pieces of protective strip is 96 feet
Step-by-step explanation:
Let the w be the width of the rectangular house and L is length. Since L = w + 16, its perimeter P = 2(w + L)
= 2(w + w + 16)
= 2(2w + 16)
Since the perimeter of the house P = 136 feet,
136 = 2(2w + 16)
dividing through by 2, we have
136/2 = (2w + 16)
68 = (2w + 16)
collecting like terms, we have
68 - 16 = 2w
52 = 2w
dividing through by 2, we have
w = 52/2
w = 26 feet.
Now, since the side walk is 3 foot wide all around, the width of the house plus sidewalk = w + 3 and the length of the house plus sidewalk = L + 3 = w + 16 + 3 = w + 19.
So, the perimeter of the house plus sidewalk which is the perimeter of the four pieces of protective strip is P' = 2(w + 3 + w + 19)
= 2(w + 22)
= 2(26 + 22)
= 2(48)
= 96 feet
So, the length of the four pieces of protective strip is 96 feet.
Answer:35in.
Step-by-step explanation:
I reccomend splitting it into sections when given problems like this.
The smaller two rectangles would be 5in * 2in which is 10in then just add them together.
For the bigger one, you'd do 5-2 in order to get the missing inches which will be 3+2 once added 5in*3in is 15in.
Finally, add 15+10+10 (15=The middle rectangle and 10=the sides)
