Find the perimeter of the polygon defined by the coordinates (5, 8), (12, 0), (-5, 0), and (-1, 8). (Round to nearest tenth)
2 answers:
Based on my created polygon, I formed a trapezoid.
I need to use the Pythagorean theorem to solve for the two sides that are the hypotenuse of the right triangles derived from the image.
1st side: distance from -1 to 5 = 6
2nd side: distance from -5 to 12 = 17
3rd side: hypotenuse:
a = -5 to -1 = 4
b = 0 t0 8 = 8
c² = 4² + 8² = 16 + 64 = 80
c = √80 = 8.94
4th side: hypotenuse:
a = 5 to 12 = 7
b = 0 to 8 = 8
c² = 7² + 8² = 49 + 64 = 113
c = √113 = 10.63
Perimeter = 6 + 17 + 8.94 + 10.63 = 42.57 or 42.6 units.
I need to use the Pythagorean theorem to solve for the two sides that are the hypotenuse of the right triangles derived from the image.
1st side: distance from -1 to 5 = 6
2nd side: distance from -5 to 12 = 17
3rd side: hypotenuse:
a = -5 to -1 = 4
b = 0 t0 8 = 8
c² = 4² + 8² = 16 + 64 = 80
c = √80 = 8.94
4th side: hypotenuse:
a = 5 to 12 = 7
b = 0 to 8 = 8
c² = 7² + 8² = 49 + 64 = 113
c = √113 = 10.63
Perimeter = 6 + 17 + 8.94 + 10.63 = 42.57 or 42.6 units.
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