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Blababa [14]
3 years ago
8

Find the perimeter of the polygon defined by the coordinates (5, 8), (12, 0), (-5, 0), and (-1, 8). (Round to nearest tenth)

Mathematics
2 answers:
a_sh-v [17]3 years ago
3 0
Based on my created polygon, I formed a trapezoid.

I need to use the Pythagorean theorem to solve for the two sides that are the hypotenuse of the right triangles derived from the image.

1st side: distance from -1 to 5 = 6
2nd side: distance from -5 to 12 = 17
3rd side: hypotenuse:
a = -5 to -1 = 4
b = 0 t0 8 = 8
c² = 4² + 8² = 16 + 64  = 80
c = √80 = 8.94

4th side: hypotenuse:
a = 5 to 12 = 7
b = 0 to 8 = 8
c² = 7² + 8² =  49 + 64 = 113
c = √113 = 10.63

Perimeter = 6 + 17 + 8.94 + 10.63 = 42.57 or 42.6 units.

Darya [45]3 years ago
3 0

Answer:

For usatestprep the answer B.) 42.6

Step-by-step explanation:


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3 years ago
Find the 61st term of -12, -28, -44,
Citrus2011 [14]

Answer:

a_{61}=-972

Step-by-step explanation:

<u>Arithmetic Sequences</u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the first terms of a sequence:

-12, -28, -44,...

Find the common difference by subtracting consecutive terms:

r = -28 - (-12) = -16

r = -44 - (-28) = -16

The first term is a1 = -12. Now we calculate the term n=61:

a_{61}=-12+(61-1)(-16)

a_{61}=-12-60*16=-12-960

\mathbf{a_{61}=-972}

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3 years ago
Write 3.25 as a mixed number in simplest form.
snow_tiger [21]
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Converting the decimal to a fraction gives;
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Read 2 more answers
In a rock-paper-scissors game, a winner gets 5 points and a loser gets 2 points. After a man played this game 20 times, his tota
aleksandr82 [10.1K]

Answer:

The man wins 9 times and looses 11 times in the rock - paper-scissor game.

Step-by-step explanation:

Let us assume that in the game:

Number of times  man wins the games = x times

Number of times  man loses the games = y times

Total number of attempts = 20

Points after winning = 5

Points after loosing = 2

Now, according to the question:

       x  + y =20

and 5 x + 2 y = 67

Now, from (1) y = 20-x,     put in (2)

5x + 2y = 67       ⇒           5x + 2(20 -x)  = 67

or, 5x -2x = 67 - 40

or, 3x = 27

⇒ x = 27/3 = 9

then y = 20 - x = 20 - 9 = 11

⇒ x = 9 and y = 11 is the solution of the given system.

Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.

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3 years ago
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