The value of x is 8.5.
Solution:
U is the mid-point of TV.
TU = 6
UV = 2x - 11
TU = UV
6 = 2x - 11
Add 11 on both sides.
6 + 11 = 2x - 11 + 11
17 = 2x
Divide by 2 on both sides.

8.5 = x
Switch the sides.
x = 8.5
Option B is the correct answer.
Angle A ~ Angle FEC
Angle B ~ Angle EFC
Angle BDA ~ Angle FCE
AB ~ EF
BD ~ FC
AD ~ EC
Answer:
4/5 * 3/2
Step-by-step explanation:
fraction division = multiplying the first fractions by the reciprocal of the second fractions (the tops are bottoms are flipped).
Ths solubility curve is used to show the amount of salt dissolved (solubility).
<h3>What is the solubility curve?</h3>
The solubility curve is a depiction of the solubility of a substance plotted against its temperature. It can be used most times to show the solubility of a susbtance at different temperatures. This question is incomplete hence so we can not be able to obtain the solubility of the salt at this temperature.
If the solubility curve has been shown in the graph, then we can be able to obtain the solubility of the salt from the data shown on the plot.
Learn more about solubility curve: brainly.com/question/9537462
Answer:
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Step-by-step explanation:
The options are missing; However, I'll simplify the given expression.
Given
![\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B32x%5E3y%5E6%7D%7D%7B%5Csqrt%5B3%5D%7B2x%5E9y%5E2%7D%20%7D)
Required
Write Equivalent Expression
To solve this expression, we'll make use of laws of indices throughout.
From laws of indices ![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So,
gives

Also from laws of indices

So, the above expression can be further simplified to

Multiply the exponents gives

Substitute
for 32


From laws of indices

This law can be applied to the expression above;
becomes

Solve exponents


From laws of indices,
; So,
gives

The expression at the numerator can be combined to give

Lastly, From laws of indices,
; So,
becomes
![\frac{\sqrt[3]{(2y)}^{4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B%282y%29%7D%5E%7B4%7D%7D%7Bx%5E2%7D)
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Hence,
is equivalent to ![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)