The answer should be X equal 5
Answer: C. Y = 5x + 5
Step-by-step explanation:
We need to write, or decide on, the equation for the blue line as this line represents the trend line for this scatter plot. We will write this in slope-intercept form. <em>See attached for a visual</em>.
First, we will find our slope. We will use
for this since we have a graph with clear points. See attached, we count up [5] and then count to the right [1] for a slope of 5.
-> Slope = 5
Now, we will find our y-intercept. This is where the line intersects the y-axis. The line hits the y-axis at point (0, 5) giving us a y-intercept of 5.
-> Y-intercept = 5
Lastly, we will write our equation and decide on an answer.
y = <em>m</em>x + <em>b</em>
y = (5)x + (5)
Y = 5x + 5
C. Y = 5x + 5
Answer:
E: L is perpendicular to a line with slope
.
Lines are perpendicular if the negative reciprocal of the slope is equal. For example, the reciprocal of
is
(remember, to get the reciprocal, simply switch the numerator and the denominator).
So, the negative reciprocal of
is
. This represents the slope of a line that is perpendicular.
Answer:
The p-value of the test statistic from the standard normal table is 0.0017 which is less than the level of significance therefore, the null hypothesis would be rejected and it can be concluded that there is sufficient evidence to support the claim that less than 20% of the pumps are inaccurate.
Step-by-step explanation:
Here, 1304 gas pumps were not pumping accurately and 5689 pumps were accurate.
x = 1304, n = 1304 + 5689 = 6993
The level of significance = 0.01
The sample proportion of pump which is not pumping accurately can be calculated as,
The claim is that the industry representative less than 20% of the pumps are inaccurate.
The hypothesis can be constructed as:
H0: p = 0.20
H1: p < 0.20
The one-sample proportion Z test will be used.
The test statistic value can be obtained as:

We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
P = 15•2046.94 = 30,704