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GREYUIT [131]
3 years ago
14

How do I evaluate 32-4x3

Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0

Answer:

20

Step-by-step explanation:

Evaluate is just simplifying so

4 times 3 is 12 times the negative makes it -12

then add 32 and -12 together

and you get 20

____ [38]3 years ago
6 0
The answer would be 20
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80% of what number is 190
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80% of 190 = 152
THE ANSWER IS 152
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2 years ago
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Ben wants to get a 94 in math class. His grade will be the average of two test scores. He scored an 89 on the first test. What g
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Answer:

Ben needs to get a 99% on his second test

Step-by-step explanation:

The average is the sum of both test scores, divided by the total number of test scores (2).

Let x by the grade Ben must receive on his second test.

(89 + x)/2 = 94

Multiply by 2 on both sides

89 + x = 188

Subtract 89 on both sides

x = 99

Check work:

(89 + 99)/2 = 188/2 = 99

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2 years ago
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A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
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Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
3 years ago
The sum of -7.68 and it’s additive inverse is??
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The answer is 0. the additive inverse of a negative number is the same number but positive. to find the sum means to add them together. for example take 2 and -2. 2 is the additive inverse of -2. if you add 2+-2 the answer comes out to 0
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3 years ago
Which decimal is between 85 and V86?
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\sf \large \underbrace{ \underline{Understanding  \: the  \: Question}}

This can be considered as a very easy Question where you have to find the value of √85 and √86 upto 2 decimal places then we could find it easily.

Let's start!

Value of √85=9.21

Value of √86=9.27

Now it is obvious that 9.25 lies between √85 and √86.

\sf \large \underbrace{ \underline{Additional \:  information}}

What are rational no.?

Any pair of numbers which is in the form of p/q where p and q are integers and p and q are co-prime is called rational number.

4 0
3 years ago
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