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Taya2010 [7]
3 years ago
14

PLEASE HELP WILL MARK BRAINLIEST

Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

explanationStep-by-step

Step-by-step explanation:

no just kidding!

<h2>Line <em>D</em></h2>

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<em>cause brain is big</em>

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<h2>*<u><em>THIS USER HAS BEEN VERIFIED AND ACCEPTED AS AN OFFICIAL BRAINLY© USER, ALLOWING THAT YOU GOT LUCKY FOR HAVING A PRO ANSWER THIS QUESTION*</em></u></h2>
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Зr2 + 6r - 4 = -2 +5
Step2247 [10]

Answer:

deciaml form would be 0.825742185

Step-by-step explanation:

5 0
3 years ago
What are two ways to determine the probability that two independent events, A and B, will occur together.
stira [4]

Two events, A and B, are independent if the fact that A occurs does not affect the probability of B occurring.

Some other examples of independent events are:

  1. Landing on heads after tossing a coin AND rolling a 5 on a single 6-sided die.
  2. Choosing a marble from a jar AND landing on heads after tossing a coin.

The events A and B are independent if any one of the following three equivalent conditions hold:

P(A ∩ B) = P(A)P(B)

P(A|B) = P(A)  B has no effect on A

P(B|A) = P(B)  A has no effect on B

Intuitively, two events are independent if the occurrence of one has no effect at all on the probability of the other.

To find the probability of two independent events that occur in sequence, find the probability of each event occurring separately, and then multiply the probabilities.

Multiplication Rule: When two events, A and B, are independent, the probability of both occurring is:

P(A and B) = P(A) · P(B)

To test whether two events A and B are independent, calculate P(A), P(B), and P(A ∩ B), and then check whether P(A ∩ B) equals P(A)P(B). If they are equal, A and B are independent; if not, they are dependent.

7 0
3 years ago
Approximately how many times greater is 2.3x10^-4 than 1.15x10^-8 ?
Minchanka [31]

Answer:

2.3 × 10^{-4} is 20,000 times greater than 1.15 × 10^{-8}

Step-by-step explanation:

Given as :

The first number= x = 2.3 × 10^{-4}

The second number= y = 1.15 × 10^{-8}

Let The first number is z times greater than second number

i.e x = z × y

Or, z = \dfrac{x}{y}

Or, z = \dfrac{2.3\times 10^{-4}}{1.15\times 10^{-8}}

Or, z = 2 × 10^{4}

∴  z = 20,000

So,The first number is 20,000 times greater than second number

Hence, 2.3 × 10^{-4} is 20,000 times greater than 1.15 × 10^{-8} . Answer

3 0
4 years ago
Do the concepts of class​ limits, marks,​ cutpoints, and midpoints make sense for qualitative​ data? Explain your answer.
tatyana61 [14]
Class limits are the smallest and the largest data value that can go into a class.

Class marks are the midpoints of the classes. They are obtained by averaging the limits.

Cutpoints are<span> specified values used to sort continuous variables into discrete categories.

</span><span>Class Midpoint is the middle value of each data class.


For qualitative data, </span>c<span>utpoints and midpoints make​ sense, but class limits and marks do​ not, since qualitative data cannot be grouped using Limit grouping.

option D.
</span>
3 0
4 years ago
Is a parroleogram a rombus
Pie

Answer:yes

Step-by-step explanation:

6 0
3 years ago
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