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1 year ago

PLEASE HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

allochka39001 [22]1 year ago

4 0

Answer:

explanationStep-by-step

Step-by-step explanation:

no just kidding!

<em>cause brain is big</em>

<h2>*<u><em>THIS USER HAS BEEN VERIFIED AND ACCEPTED AS AN OFFICIAL BRAINLY© USER, ALLOWING THAT YOU GOT LUCKY FOR HAVING A PRO ANSWER THIS QUESTION*</em></u></h2>

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Elena rode her bike 2 miles in 10 minutes. She rode at a constant speed. Complete the table to show the time it took her to trav

harkovskaia [24]

1 mile per 5 minutes

2:10

3:15

4:20 (Nice)

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so on and so forth.

8 0

2 years ago

Read 2 more answers

Please help a step by step would be nice answer is also ok

nasty-shy [4]

I would choose A I’m not to sure tho

6 0

2 years ago

4x+3y=23 x-5y=0 using substitution

Andrei [34K]

Answer:

{x,y} = {115/17,-23/17}

Step-by-step explanation:

I believe its true.

8 0

1 year ago

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

2 years ago

Divide x5+15x4+54x3−25x2−75x−34 by x+8.

Wittaler [7]

we are given

$x^5+15x^4+54x^3-25x^2-75x-34$

divide by x+8

we can use long division

so, we will get

$Quotient=x^4+7x^3-2x^2 -9x-3$

$Remainder=-10$

we can also write it as

$\frac{x^5+15x^4+54x^3-25x^2-75x-34 }{x+8}=(x^4+7x^3-2x^2 -9x-3)-\frac{10}{x+8}$ ..............Answer

3 0

2 years ago