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vlabodo [156]
2 years ago
8

A bag has 4 green marbles, 3 red marbles, and 3 yellow marbles. What is the probability that you pick. a red marble, do not repl

ace it, and pick another yellow marble?
Mathematics
1 answer:
Illusion [34]2 years ago
7 0

Answer:

Red is 3/10

yellow is 1/3

Step-by-step explanation:

since there is 10 marbles all together it will be out of 10

and since there is 3 red marbles the probability is 3/10

but when you take out one of the marbles the total amount of marbles in the bag is 9. since there is 3 yellow marbles in the bag it would be 3/9 which can be simplified to 1/3

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Given x=2 and y=4, then x*2 y is
Zarrin [17]

Answer:

16 I guess

Step-by-step explanation:

2*2 is 4

Then 4 times 4 is 16.

7 0
3 years ago
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One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo
almond37 [142]

Answer:

(1) P(\bar X < 26 inches) = 0.0436

(2) P(27.5 inches < \bar X < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let \bar X = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

            Z = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean vertical  leap = 28 inches

            \sigma = standard deviation = 7 inches

            n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P(\bar X < 26 inches)

   P(\bar X < 26) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{26-28}{\frac{7}{\sqrt{36} } } ) = P(Z < -1.71) = 1 - P(Z \leq 1.71)

                                                 = 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < \bar X < 28.5 inches) = P(\bar X < 28.5 inches) - P(\bar X \leq 27.5 inches)

    P(\bar X < 28.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{28.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z < 0.36) = 0.64058 {using z table}                      

    P(\bar X \leq 27.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{27.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z \leq -0.36) = 1 - P(Z < 0.36)

                                                        = 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < \bar X < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0
3 years ago
At 10 am a 6-foot- tall man casts a 4.5 foot shadow. How long a shadow cast by a 50-foot tree?
astra-53 [7]
It should be a 39 foot shadow

4 0
3 years ago
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Quick help guys thanks :)
Sonbull [250]

Answer:

\large\boxed{t^{-58}u^{-88}v^{-71}w^{-1}}

Step-by-step explanation:

\dfrac{tuv^4w^0}{t^{59}u^{89}v^{75}w}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=t^{1-59}u^{1-89}v^{4-75}w^{0-1}=t^{-58}u^{-88}v^{-71}w^{-1}

8 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!
Triss [41]

Answer:

The Blue box is your answer

Step-by-step explanation:

Multiply 4, 8, and 7 and you get 224. The problem states that it should not be over 250, and 224 is not over 250. So the blue box is your best go.

5 0
2 years ago
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