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3 years ago

A teacher had 70 packages of paper she wanted to split equally into 7 piles. How much should be in each pile?

Mathematics

1 answer:

MatroZZZ [7]3 years ago

3 0

Answer:

Step-by-step explanation:

$70\div7=10$

There are 10 packages of paper in each pile.

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Check:

There are 7 piles.

Thus, there are $7*10=70$ total packages of paper.

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50 points! Mhanifa please help! I would appreciate it! Random answers will be reported!

alisha [4.7K]

Answer:

x = 4, ∠I = 33°

Step-by-step explanation:

<u>Question 1</u>

Converse to Base Angles Theorem: 28 = 9x - 8,

28 = 9x - 8 (add 8 to both sides)

9x = 36 (divide both sides by 9)

x = 4

<u>Question 2</u>

Since the triangles are congruent, ∠A ≅ ∠G:

∠A = 55 = ∠G

If we consider triangle ALX we have ∠L = 180-55-92 = 33°

And since ∠L ≅ ∠I, ∠I = 33° respectively

4 0

2 years ago

Read 2 more answers

Can someone please help me ??

adelina 88 [10]

Answer:

Step-by-step explanation:

The values are not vectors so ST/SR should be 3

6 0

2 years ago

A printer takes 30 minutes to print a banner and a poster. I will take 50 minutes to print a banner and three posters. How long

qwelly [4]

Answer:

It takes the printer 20 minutes to print a banner

Step-by-step explanation:

Notice that there are two unknowns in this problem: the time to print a poster and the time to print a banner. Let's assign the letter "b" to the time it takes to print a banner, and "p' the time it takes to print a poster.

So we can write the following two equations involving the total amount of time that takes to print in the two cases:

$b+p=30\\b+3p=50$

We can solve for the unknown "p" by subtracting term by term in the equation set above:

$b+3p=50\\b+p=30\\\\b-b+3p-p=50-30\\2p=20\\p=10$

So it takes 10 minutes to print each poster, we can find the time it takes to print the banner by using the value we just found in one of the equations:

$b+p=30\\b+10=30\\b=20$

So, it takes 20 minutes to print a banner.

8 0

3 years ago

4. Determine all unknown sides and angles to 1 decimal place.

Ksju [112]

Answer:

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees

Step-by-step explanation:

4a) Given the following

Opposite side = 38cm (side facing the given angle)

Required

Adjacent and hypotenuse side

According to SOH CAH TOA

$tan \theta = \frac{opp}{hyp}\\tan 32=\frac{38}{hyp}\\hyp=\frac{38}{tan 32}\\hyp=\frac{38}{0.6249}\\hyp= 60.81cm$

Next is to get the adjacent

$Cos 32=\frac{adj}{60.81}\\adj=60.81cos32\\adj=60.81(0.8480)\\adj= 51.57cm$

Next is to get the missing

Since sum of angle in the triangle is 180degrees

32 + 90 + x = 180

122 + x = 180

x = 180 - 122

x = 58degrees

7 0

3 years ago

X3= one over eight what's the answer for that?

Black_prince [1.1K]

X^3 = 1/8
x^3 = (1/2)^3
x = 1/2

hope it helps

6 0

2 years ago