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kenny6666 [7]
3 years ago
12

Let f(x)= 2x2−3x+8 What is the value of f(-4)?

Mathematics
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer:

52

Step-by-step explanation:

So we have the function:

f(x)=2x^2-3x+8\\

And we want to find f(-4).

To find f(-4), substitute -4 for x. Thus:

f(-4)=2(-4)^2-3(-4)+8

Square:

f(-4)=2(16)-3(-4)+8

Multiply:

f(-4)=32+12+8

Add:

f(-4)=44+8

Add:

f(-4)=52

And we're done!

Our answer is 52.

-Dominant- [34]3 years ago
4 0

Answer:

f(-4)=52

Step-by-step explanation:

We are given the function:

f(x)=2x^2-3x+8

We want to find f(-4), so we must substitute -4 in for x.

f(-4)=2(-4)^2-3(-4)+8

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Evaluate the exponent first.

⇒ (-4)²= -4*-4 = 16

f(-4)=2(16)-3(-4)+8

Multiply 2 and 16.

⇒ 2*16=32

f(-4)=32-3(-4)+8

Multiply -3 and -4.

⇒-3*-4=12

f(-4)=32+12+8

Add the three numbers together.

f(-4)=44+8\\\\f(-4)=52

f(-4) for the function f(x)=2x²-3x+8 is equal to 52

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