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Ber [7]
3 years ago
15

He memory unit of a computer has 2 20 words. The computer has instruction format with four fields; an operation code field, a mo

de field to specify one of 4 addressing modes, a register address field to specify one of 6 5 processor registers, and a memory address.
Assume an instruction is 32 bits long. Answer the following:
A: How large must the mode field be? B: How large must the register field be? C: How large must the address field be? D: How large is the opcode field?
Computers and Technology
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

Opcode = 3

Mode =2

RegisterRegister =7

AR = 20

Explanation:

a) Number of addressing modes = 4 = 22 , So it needs 2 bits for 4 values

Number of registers = 65 = 1000001 in binary , So it needs 7 bits

AR = 20

Bits left for opcode = 32 -(2+7+20) = 3

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3 years ago
In a print statement, you can set the __________ argument to a space or empty string to stop the output from advancing to a new
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In a print statement, you can set the End argument to a space or empty string to stop the output from advancing to a new line.

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6 0
2 years ago
Where can I learn how to make my own video game for free?
Sladkaya [172]
Game’s top rack not top pop
4 0
3 years ago
Read 2 more answers
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8 0
2 years ago
Consider the unsigned decimal number 35. What is the value in hexadecimal?<br><br> 1. 3510 = ____ 16
Liula [17]

Answer:

23_{16}

Explanation:

When we convert any decimal number into the hexadecimal number we have to divide that number with 16.

Now according to question the decimal number is 35.

Now to convert this in hexadecimal divide it with 16.

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8 0
3 years ago
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