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8_murik_8 [283]

2 years ago

14

In a print statement, you can set the __________ argument to a space or empty string to stop the output from advancing to a new

line.

Computers and Technology

1 answer:

jeka942 years ago

6 0

In a print statement, you can set the End argument to a space or empty string to stop the output from advancing to a new line.

<h3>What is a Print statement?</h3>

A print "statement" is known to be a kind of statement that looks like a call to the make (print) or println process of the System.

Note that In a print statement, you can set the End argument to a space or empty string to stop the output from advancing to a new line so that it can work properly.

Learn more about print statement from

brainly.com/question/25220385

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How does voting help in a social news site?

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It helps spread the word about certain candidates in an upcoming election.

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3 years ago

Which method can be used to write data to a text file opened with the BufferedWriter object outfile?

maksim [4K]

Answer:

Option (d) outfile.write();

Explanation:

As the object created for the class BufferedWriter is outfile, outfile.write is the correct syntax for writing in a text file. Here, write is the method used for writing into a text file. The data present is written in the textfile. Here, the text file is opened before writing the text into the file. Option (d) is correct.

Option (a) outfile.newLine(); is used to separate the lines. This is used to break the existing lines into smaller lines. This can also be used to start a new line. Here, newLine() is the method.So, option (a) is not suitable.

Option (b) outfile.existLine(); This is not a valid syntax as there is no method called existLine() in the class BufferedWriter. So, this is a wrong option.

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3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

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Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

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3 years ago

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Rudiy27

Explanation:

To move substances against a concentration or electrochemical gradient, the cell must utilize energy in the form of ATP during active transport. Primary active transport, which is directly dependent on ATP, moves ions across a membrane and creates a difference in charge across that membrane.

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