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Nina [5.8K]
3 years ago
13

Sound is more effectively transmitted into a stethoscope by direct contact than through the air, and it is further intensified b

y being concentrated on the smaller area of the eardrum. It is reasonable to assume that sound is transmitted into a stethoscope 100 times as effectively compared with transmission though the air. What, then, is the gain in decibels produced by a stethoscope that has a sound gathering area of 15.0 cm2, and concentrates the sound onto two eardrums with a total area of 0.800 cm2 with an efficiency of 38.0%?
Medicine
1 answer:
zhenek [66]3 years ago
3 0

Answer: Δβ = 28.5278 dB

Explanation:

from the question we are given that;

the sound gathering area Ga = 15.0 cm²

total area Ae = 0.800 cm²

efficiency ε = 38 %

therefore we have that the effective gathering area of the stethoscope is;

As = ε Ga

As = 38 % × 15 = 5.7 cm²

But I ∝ 1/A

where Ie/Is = As/Ae

Ie/Is = 5.7/0.800 = 7.125

given that we are to assume that  sound is transmitted into a stethoscope 100 times, this gives

I'e/I's = Ie/Is × 100 = 7.125 × 100 = 712.5

Δβ = βe - βs = (10dB) log (I'e/Io) - (10dB) log (I's/Io)

Δβ = (10dB) log (I'e/I's)

Δβ = (10dB) log (712.5) = 28.5278

Δβ = 28.5278 dB

cheers i hope this helps

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