It is very important to go through all the details that have been provided in the question. These information's will come in very handy while getting to the solution for the answer. Now let us concentrate on the problem in hand.
Distance between Bristol and Rome that the plane covers = 1200 miles
Starting time of the plane from Bristol = 14:00 hrs
Landing time of the plane in Rome = 17:15 hrs
Then
Total time taken by the plane to travel from Bristol to Rome = 17:15 - 14:00 hours
= 3 .15 hours
So
The average speed of the plane = 1200/3.15 miles per hour
= 380.95 miles per hour
From the above deduction we can conclude that the average speed of the plane traveling from Bristol to Rome is 380.95 miles per hour.
2000* 100= 200,000 is the answer
SinA /a = sin C / c
sin 60/9 = sin C / 10
(√3/2)/9 = sinC/ 10
√3/18 = sin C / 10
so c will be sin inverse ((10√3)/10)
In order to solve this problem, the approach should be formulating equations such that they form a system of linear equations. Let's start by assigning variables. Let x be the number of homeruns made by Peter, and y be the number of homeruns made by Alice. Therefore,
x = 2(y - 6)
This is the equation for the relationship between Peter's and Alice's hits. The second equation would be the sum of their hits:
x + y = 18
These are the two independent equations in order to solve the two unknowns, x and y. Substituting the first equation into the second equation,
2(y - 6) + y = 18
2y - 12 + y = 18
3y = 18 + 12
3y = 30
y = 10
Using y=10 to the first equation:
x = 2(10 - 6)
x = 8
Therefore, Peter made 8 homeruns, while Alice made 10 homeruns for a total of 18.
Hello :
the set of all points M (x,y) equidistant from the points A(−1, 6, 3)
and B(4, 3, −2):
MA = MB or MA² = MB²
an equation is :
(x+1)²+(y -6)²+(z - 3)² = (x - 4)² +(y -3)² + (z+2)²
