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KiRa [710]
2 years ago
7

Does anyone know how to do this, I’m failing math and I need this to boost my grade. Someone help please

Mathematics
1 answer:
Nataly [62]2 years ago
8 0

Answer:

Step-by-step explanation:

Hey, I'm not sure if I am right, but I hope it can create a spark or something.

8. Find x

10x - 1 = 14x - 37      Combine like terms

     +37        +37

10x + 36 = 14x          Combine like terms

-10x          -10x

    36 = 4x                Divide to isolate x

    <u>36</u> = <u>4x</u>

     4      4

    9 = x        

You can also do this method with the others.

PS: I am still not sure if this is the right method, lol. I just really want to help.

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Use the Integral Test to determine whether the series is convergent or divergent
Inga [223]

Answer:

A. \sum_{n=1}^{\infty}\frac{n}{e^{15n}} converges by integral test

Step-by-step explanation:

A. At first we need to verify that the function which the series is related (\frac{n}{e^{15n}}) fills the necessary conditions to ensure that the test is effective.

*f(x) must be continuous or differentiable

*f(x) must be positive and decreasing

Let´s verify that f(x)=\frac{n}{e^{15n}} fills these conditions:

*Considering that eˣ≠0 for all x, the function f(x)=\frac{n}{e^{15n}} does not have any discontinuities, so it´s continuous

*Because eˣ is increasing:

      if a<b ,then eᵃ<eᵇ

      if 0<eᵃ<eᵇ ,then 1/eᵃ > 1/eᵇ

      if 1/eᵃ > 1/eᵇ and a<b, then a/eᵃ<b/eᵇ

  We conclude that f(x)=\frac{n}{e^{15n}} is decreasing

*Because eˣ is always positive and the sum is going from 1 to ∞, this show that f(x)=\frac{n}{e^{15n}} is positive in [1,∞).

Now we are able to use the integral test in f(x)=\frac{n}{e^{15n}} as follows:

\sum_{n=1}^{\infty}\frac{n}{e^{15n}}\ converges\ \leftrightarrow\ \int_{1}^{\infty}\frac{x}{e^{15x}}\ dx\ converges

Let´s proceed to integrate f(x) using integration by parts

\int_{1}^{\infty}\frac{x}{e^{15x}}\ dx=\int_{1}^{\infty}xe^{-15x}\ dx

Choose your U and dV like this:

U=x\ \rightarrow dU=1\\ dV=e^{-15x}\ \rightarrow V=\frac{-e^{-15x}}{15}

And continue using the formula for integration by parts:

\int_{1}^{\infty}Udv = UV|_{1}^{\infty} - \int_{1}^{\infty}Vdu

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{-1}{15} \int_{1}^{\infty}e^{-15x}\ dx

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{-1}{15}(\frac{-1}{15e^{15x}})|_{1}^{\infty}

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{1}{225e^{15x}}|_{1}^{\infty}

Because we are dealing with ∞, we´d rewrite it as a limit that will help us at the end of the integral:

\int_{1}^{\infty}xe^{-15x}\ dx= \lim_{b \to{\infty}}(\frac{-x}{15e^{15x}}|_{1}^{b}-\frac{1}{225e^{15x}}|_{1}^{b})

\int_{1}^{\infty}xe^{-15x}\ dx= \lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}}-(\frac{-1}{15e^{15}}-\frac{1}{225e^{15}})

\int_{1}^{\infty}xe^{-15x}\ dx= ( \lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}})+\frac{1}{15e^{15}}(1-\frac{1}{15})

We only have left to solve the limits, but because b goes to  ∞ and it is in an exponential function on the denominator everything goes to 0

\lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}} = 0

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{1}{15e^{15}}(1-\frac{1}{15})

Showing that the integral converges, it´s the same as showing that the series converges.

By the integral test \sum_{n=1}^{\infty}\frac{n}{e^{15n}} converges

7 0
3 years ago
Cheese pizza cost 6$ each and four topping pizza that cost $10 each. If you order c cheese pizzas and f four toppings how much w
son4ous [18]

Answer:

Total = \$6c + \$10f

Step-by-step explanation:

Given

Cheese\ Pizza = \$6

Topping\ Pizza = \$10

Required

Cost of c cheese and f topping pizza

Solving for c cheese pizza

If 1 cheese pizza costs $6,

c cheese pizza would cost $6 * c

Solving for f topping pizza

If 1 topping pizza costs $10,

f topping pizza would cost $10 * f

Hence:

Total = \$6 * c + \$10 * f

Total = \$6c + \$10f

<em>Hence, the total amount paid is: </em>\$6c + \$10f<em></em>

6 0
3 years ago
A cotton candy vendor has 22 cones of blue cotton candy to sell. If the blue cotton candy is 50% of the total number of cones, h
Feliz [49]
44. You can come to this answer by using algebra,
1/2x = 22
Multiply both sides by 2(denominator) thus,
X = 44.
Or you can use lateral thinking and realise that if 22 is 50%, you need to multiply by 2 to reach 100%.
4 0
3 years ago
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PLS HELPPP !<br><br>The answer is D.<br>can anyone explain why?
Semmy [17]
Electricity wasn't the only energy cost. also look at logs for fire. being that they were bought for fire it is using heat energy. there for making the total energy cost the highest. only look at what is energy cost toward the overall bill.
6 0
3 years ago
Heights of men on a baseball team have a? bell-shaped distribution with a mean of 177 cm177 cm and a standard deviation of 8 cm8
Assoli18 [71]
I don't think there is a way to answer your question.
8 0
3 years ago
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