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bezimeni [28]
3 years ago
11

Arrange the following in descending order. 5/8, 1/20, 7/8​

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

7/8, 5/8. 1/20

Step-by-step explanation:

7/8 is close to 1

5/8 is close to half of 1

1/20 is closer to zero than it is to 1

therefore, 7/8 is the largest number, 1/20 is the smallest number, and 5/8 is in between them

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it is in answer

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2 years ago
How do you redraw a scale drawing with a new scale
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 Take measurements of what you want to draw, (e.g. a simple cube that is 100 cm x 100 cm x 100 cm.) 
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3 0
2 years ago
I had a summer job cooking two items at a bbq place. I sell burgers for $9.00 and sell chicken sandwiches for $11.25. Because I
pishuonlain [190]

Answer:

He sold 180 chicken sandwiches and 150 burguers.

Step-by-step explanation:

Since 330 items were sold, then the amount of burguers and chicken sandwiches sold must be equal to this value. From this information we have:

burguers + sandwiches = 330

We know that each burguer cost $9 and each chicken sandwich cost $11.25 and that we made a total of $3,375. So we have:

9*burguers + 11.25*sandwiches = 3,375

From the first equation we have:

burguers = 330 - sandwiches

Applying it on the second equation:

9*(330 - sandwiches) + 11.25*sandwiches = 3,375

2,970 - 9*sandwiches + 11.25*sandwiches = 3,375

2.25*sandwiches = 3,375 - 2,970

2.25*sandwiches = 405

sandwiches = 405/2.25 = 180

So,

burguers = 330 - 180  = 150

He sold 180 chicken sandwiches and 150 burguers.

8 0
2 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)<br><br> Find the inverse of :
muminat

Answer:

h^{-1}(x) = \dfrac{5x - 6}{2}

Step-by-step explanation:

h(x)= \dfrac{2x + 6}{5}

(a) Rename h(x) as y  

y = \dfrac{ 2x+ 6}{5}

(b) Solve for x :  

\begin{array}{rcl}y& = &\dfrac{2x + 6}{5}\\\\5y & = & 2x + 6\\5y - 6 & = & 2x\\x & = & \mathbf{\dfrac{5y - 6}{2}}\end{array}

(d) Switch x and y  

y = \dfrac{5x -6}{2}

(e) Rename y as the inverse function  

h^{-1}(x) = \mathbf{\dfrac{5x - 6}{2}}

The graphs of inverse functions are reflections of each other across the line y = x.

In the diagram, the graph of h⁻¹(x) is the reflection of h(x) about the line y = x.

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2 years ago
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