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Lady bird [3.3K]
3 years ago
14

Solve the following equation 6x-3=4z+9

Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

z=1.5

Step-by-step explanation:

Simplifying

6z + 3 + -4z = 9

Reorder the terms:

3 + 6z + -4z = 9

Combine like terms: 6z + -4z = 2z

3 + 2z = 9

Solving

3 + 2z = 9

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3' to each side of the equation.

3 + -3 + 2z = 9 + -3

Combine like terms: 3 + -3 = 0

0 + 2z = 9 + -3

2z = 9 + -3

Combine like terms: 9 + -3 = 6

2z = 6

Divide each side by '2'.

z = 3

Simplifying

z = 3

astra-53 [7]3 years ago
8 0
6386 thank you very much
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D(1)=3 d(n) = d(n-1) - 14 what is the third term in the sequence
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6 0
3 years ago
Solve. Write the solution in interval notation. -2x>-8 and -5x<20.
Novosadov [1.4K]

Answer:

The interval notation of the solution is (-4 , 4)

Step-by-step explanation:

* Let us explain a very important point in solving inequality

- When you multiply or divide an inequality by negative number we

   must reverse the symbol of the inequality

- Ex:

∵ 2 < 3

- If we multiply the both sides of the inequality by -1, then the

  inequality will be -2 < -3 and this is completely wrong, so we must

  reverse the symbol of the inequality

∴ -2 > -3

* Now let us solve the problem

∵ -2x > -8

- Divide both sides by -2 and remember to reverse the symbol of the

  inequality

∴ x < 4

∵ -5x < 20

- Divide both sides by -5 and remember to reverse the symbol of the

  inequality

∴ x > -4

- From both solutions

∴ -4 < x < 4

∴ The solution is {x : -4 < x < 4}

- Interval notation is a way of writing the solutions of inequalities

 ( , ) if x does not equal the end numbers

 [ , ] if x equals the end numbers

 [ , ) , ( , ] if x equals one of the two end numbers

* The interval notation of the solution is (-4 , 4)

4 0
3 years ago
The base of a solid in the first quadrant of the xy plane is a right triangle bounded by the coordinate axes and the line x + y
Ivahew [28]

The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is 

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Integrating from x = 0 to x = 1, we have 

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= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144. 

Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...

8 0
3 years ago
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Sidana [21]

Answer:

m>7 = 142°

Step-by-step explanation:

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3 0
3 years ago
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