Solve the following equation 6x-3=4z+9
2 answers:
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Answer:
a) P(three tails) =
b) P(two tails followed by one head) =
Step-by-step explanation:
coin is tossed three times so, outcome is
HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.
Hence sample space will be
S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}
chance of getting three tails is '1' i.e. TTT
hence,
P(three tails) =
two tails followed by one head is TTH
so, chance of getting that outcome is also '1'
hence,
P(two tails followed by one head) =
Answer:
-5/13
Step-by-step explanation:
sin theta = opp / hyp
sin theta = -12 /13
we can find the adj side by using the pythagorean theorem
adj^2 + opp ^2 = hyp^2
adj^2 +(-12)^2 = 13^2
adj^2 +144 =169
adj^2 = 169-144
adj^2 = 25
Taking the square root of each side
adj = ±5
We know that it has to be negative since it is in the third quad
adj = -5
cos theta = adj / hyp
cos theta = -5/13
