The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
Refer to the attached image.
As we can observe ABCD is a square, whose corners that is A,B,C and D lie on the circle.
The diameter AC = 0.35 meter.
We have to find the side of square.
Let the measure of side of a square be 'l' meter
In triangle ABC,
By Pythagoras theorem, we get





So, l = 0.25 meter
Therefore, the measure of side of the square is 0.25 meter.
Hi, I would be glad to help you here.
<span>7x − 2 < 3 + 2x
Move terms
7x - 2x - 2 < 3
Collect the like terms
(7x - 2x) = 5x (<3 + 2 stays the same)
Calculate
5x (<3 + 2 = 5)
5x <5
Divide both sides of the inequality by (5) giving you,
x < 1
So, finally in a total the correct answer here is (x < 1)
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