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stepan [7]
4 years ago
9

there are 75 students in school band 45 students play woodwind instruments what percent of students play woodwinds

Mathematics
2 answers:
Ratling [72]4 years ago
8 0
45/75 play woodwind
that simplified is 3/5
SOVA2 [1]4 years ago
8 0
So here is what we know
75 students are in the band
45 play woodwinds
Now let me make an expression(I use this usually)
part/whole=%/100
So we know the part is 45 and the whole is 75, and we don't know the %
So let us substitute those values...
45/75=%/100
Lets simplify 45/75
45/75 divided by 15/15= 3/5
So lets get back to our expression
3/5=%/100
5 x 20 is 100 so 3 x 20 is 60 
So 60% of the students is the correct answer
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givi [52]
Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.

1735.97-100=1635.97

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7 0
2 years ago
Melaine charges $4.50 per hour when she washes cars, plus $5.00 for supplies. Which function rule represents the amount y melain
spayn [35]

Answer:

B y= 4.50x + 5.00

Step-by-step explanation:

4.50 is the “mx” in y=mx+b also known as the Slope that moves.

the 5 is the ”b” which is the y-intercept. It is a constant and does not change.

4 0
3 years ago
A family spent a total of $1946 on fast food this year. If this family decreases the amount it spends on fast food by 3% every y
prohojiy [21]
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8 0
3 years ago
Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the a
d1i1m1o1n [39]

Answer:

see below

Step-by-step explanation:

16x^2 − 8x + 1

(4x)^2 -8x +1

Factor

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a^2 -2ab +b^2 = (a-b)(a-b)

(4x)^2 -8x +1 = (4x-1) (4x-1)

The area of a square is given by

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4x-1 = s

The side length is 4x-1

(81x^2 − 4y^2)

(9x)^2 - (2y)^2

This is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(9x-2) (9x+2)

The area of a rectangle is

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3 0
3 years ago
Solve triangle ABC, when A= 6, B=10 and c=12
valentinak56 [21]
Use cosine rule,

cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)

cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)

cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
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C=93.823 degrees.................................(C)

Check:29.926+56.251+93.823=180.0 degrees....ok
5 0
3 years ago
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