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zavuch27 [327]
4 years ago
9

The end points of one side of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the pentagon?

Mathematics
1 answer:
marissa [1.9K]4 years ago
8 0
To determine the perimeter of the pentagon, you must first calculate a side length of it. Let's name the coordinates A(-1,4) and B(2,3).

To figure out how far the points are from each other, you have to use the distance formula:
D_{AB}  =  \sqrt{( x_{2}-x_{1})^2+{(y_{2}-y_{1})^2}

x_{1} =1, x_{2} =-2, y_{1} =2, y_{2} =3
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2}
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2} 
D_{AB}= \sqrt{(2+1)^2+{(3-4)^2}
D_{AB}= \sqrt{(3)^2+(-1)^2}
D_{AB}= \sqrt{9+1}
D_{AB}= \sqrt{10}

Now, the formula for the perimeter of a pentagon is 
P = 5×side length
 
So...
Perimeter = 5×\sqrt{10}

The answer is (2)

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Find three consecutive even integers such that the sum of the squares of the first two is four less than twice the square of the
velikii [3]

Answer:

the three consecutive even integers are -2, 0, 2

Step-by-step explanation:

Let the first even integer = n

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Let the third even integer = n + 4

From the given statement, we form the equation below

(n²) + (n + 2)²  + 4 = 2(n + 4)²

Expand this equation;

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collect like terms together;

2n² - 2n² + 4n - 16n = 32 - 8

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n = -2

Second integer = n + 2

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Therefore, the three consecutive even integers are -2, 0, 2

6 0
3 years ago
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iVinArrow [24]

Transformations:

1.) The -4 moves your y-intercept down 4 units. Without the -4, your y-intercept would be (0,-1)

2.) The -2 in the fraction moves your x-intercept to the to the right 2 units. Without the -2, your x-intercept would be (1/2,0)

Domain:

(-∞,2) ∪ (2,∞)

Range:

(-∞,-4) ∪ (-4,∞)

Vertical Asymptote:

x=2

Horizontal Asymptote:

y=-4

X-Intercept:

(5/2,0)

Y-Intercept:

(0,-5)

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Read 2 more answers
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