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zavuch27 [327]
3 years ago
9

The end points of one side of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the pentagon?

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0
To determine the perimeter of the pentagon, you must first calculate a side length of it. Let's name the coordinates A(-1,4) and B(2,3).

To figure out how far the points are from each other, you have to use the distance formula:
D_{AB}  =  \sqrt{( x_{2}-x_{1})^2+{(y_{2}-y_{1})^2}

x_{1} =1, x_{2} =-2, y_{1} =2, y_{2} =3
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2}
D_{AB}= \sqrt{(2--1)^2+{(3-4)^2} 
D_{AB}= \sqrt{(2+1)^2+{(3-4)^2}
D_{AB}= \sqrt{(3)^2+(-1)^2}
D_{AB}= \sqrt{9+1}
D_{AB}= \sqrt{10}

Now, the formula for the perimeter of a pentagon is 
P = 5×side length
 
So...
Perimeter = 5×\sqrt{10}

The answer is (2)

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Answer:

x = 15.33

Step-by-step explanation:

3y is equal to 2x + 13. The reason why is because they are corresponding angles, (right next to each other). From there, you would have to substitute y into 3y. The equation should look like: 3(23) = 2x + 13. All that is left is to solve for x.

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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

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