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Ad libitum [116K]
3 years ago
11

2. In the data set below, what is the median? 9, 4, 9, 2, 8, 2,1 a. 9 b. 1 с. 2 d. 4​

Mathematics
2 answers:
Marrrta [24]3 years ago
6 0

Answer:

d

Step-by-step explanation:

it's 4 because I'd you put the numbers from least to greatest its in the middle

Sholpan [36]3 years ago
4 0

Answer:

2

Step-by-step explanation:

arrange the numbers in order

count how many numbers you have

if have ood number divide by 2 and round up to get the position of the median number

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PLEASE HELP ME PLEASE
andreev551 [17]
There is no solution is the answer. I had this in one of my math tests so I'm positive it's correct :D 
4 0
4 years ago
XD Plzzzzzz do 2 slides (4 problems)
Leya [2.2K]

Answer:

Slide 1:

1. Solution = (-3,2)

<em>y = 2x - 1</em>

<em>y = 3/2x + 6</em>

2. No solution

<em>y = -4/2x + 4</em>

<em>y = -4/2x - 5</em>

Slide 2:

3. Solution = (1, -6) ONE SOLUTION

4. Solution = (-4, -1) ONE SOLUTION

p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4

I really hope this helped :)

6 0
3 years ago
Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
3 years ago
Enter the expression using exponents. 1\2 × 1\2 × 1\2 × 1\2 × 1\2 × 1\2 × 1\2
Ad libitum [116K]

Answer:

<h2>1/2⁷</h2>

Step-by-step explanation:

1/2 is multiplied by itself 7 times, thus an exponent of 7.

I'm always happy to help :)

3 0
3 years ago
Read 2 more answers
11 billion in scientific notation
saw5 [17]
11000000000
1.1 x 10^10

Billion has 9 zeros.
4 0
3 years ago
Read 2 more answers
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