Explanation:
no 3 is the correct answer I think...
Answer:
Plant cells will be unable to perform glycolysis due to the inhibitor and will die.
Explanation:
Glucose is a high energy stable compound.Therefore in order to extract the stored energy for cellular use, it must be broken down. The addition of inorganic Phosphate ions(Pi) to 6-carbon glucose compound in the presence of 2ATP molecules is called Phosphorylation. This phosphorylation reaction is catalyse by Hexokinase.
The 6C-glucose is spitted to 6C-Fructose phosphate, and to 6C-fructose biphophate. The later is converted to 2molecules of 3Carbon compounds called triose phosphate.
It is during the conversion of 2-molecules of 3C- triphosphate to Pyruvate that yields 2 ATPs per molecule of glucose.
Therefore if hexokinase is inhibited , then the glucose phosphorylation can not occur. Hence the sequence of events as Glycolytic pathways that leads to production of ATP during formation of Pyruvate can not occur.
Definitely, plant cells biochemical reactions will seize, glycolytic pathways will be inhibited, ATPs will not be synthesized,leading to plant cells deaths.
IAIA IAiO IBIB IBiO IAIB iOiO
These are the blood types: A, A, B, B, AB, and O, respectively.
Since both A and B are dominant to O, which is recessive, they share the trait when both expressed (type AB).
This is called [B. Codominance.]
Because lung transplants can easily fail and most of the time lungs are so vulnerable to infection.
