Answer:
the quadratic formula is ax^2 + bx + c", if the first one is expanded out I will be 6x^2+8x+27 so that's the answer
1.Choice 4: 10
2. Choice 1: Add 5.2 to both sides if the equation.
Answer:

Step-by-step explanation:
Given
--- interval
Required
The probability density of the volume of the cube
The volume of a cube is:

For a uniform distribution, we have:

and

implies that:

So, we have:

Solve


Recall that:

Make x the subject

So, the cumulative density is:

becomes

The CDF is:

Integrate
![F(x) = [v]\limits^{v^\frac{1}{3}}_9](https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Bv%5D%5Climits%5E%7Bv%5E%5Cfrac%7B1%7D%7B3%7D%7D_9)
Expand

The density function of the volume F(v) is:

Differentiate F(x) to give:




So:

Answer:
Step-by-step explanation:
Since they already have a common denominator of x+1 we can add the numerators
(2x+4-x+5)/(x+1)
(x+9)/(x+1)
So measure the pen in meters