All categories

3 years ago

80 points!!

Mathematics

2 answers:

SSSSS [86.1K]3 years ago

7 0

Answer: 27.7

Step-by-step explanation: i took the quiz

sesenic [268]3 years ago

4 0

Answer:

27.7

Step-by-step explanation:

You might be interested in

Ethan says it would require more than 100 moons to equal the mass of the Earth. Is this correct? Support your answer with your w

vivado [14]

Answer:

Step-by-step explanation:

because,THE MOON IS SMALLER ACROSS (IN DIAMETER) THAN THE UNITED STATES IS WIDE. If the Earth were hollow, about 50 moons would fit inside. a. THE MOON IS SMALLER THAN THE EARTH: FIFTY MOONS WOULD FILL THE EARTH.

3 0

3 years ago

Which statement proves that quadrilateral HIJK is a kite? HI ⊥ IJ, and m∠H = m∠J. IH = IJ = 3 and JK = HK = StartRoot 29 EndRoot

olchik [2.2K]

The statement proves that quadrilateral HIJK is a kite is IH = IJ = 3 and JK = HK = $\sqrt{29}$ and IH ≠ JK and IJ ≠ HK.

Given

On a coordinate plane, kite H I J K with diagonals is shown.

Point H is at (negative 3, 1), the point I is at (negative 3, 4), point J is at (0, 4), and point K is at (2, negative 1).

A quadrilateral is called a kite with two pairs of equal adjacent sides but unequal opposite sides.

Firstly calculating the length of the sides of the kite using the following formula;

$\rm Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For a kite quadrilateral, HIJK will be a kite, if it's siding IJ = IH

From the graph length of I H = 4 - 1 = 3 units

Length of IJ = 0 - (-3) = 3 units

Therefore, IJ = IH = 3 units

Sides HK should be equal to JK

Length of HK is;

$\rm HK =\sqrt{(1-(-1))^2+(2-(-3))^2} \\\\HK=\sqrt{(1+1)^2+(2+3)^2} \\\\HK=\sqrt{(2)^2+(5)^2\\} \\\\ HK =\sqrt{4+25} \\\\HK= \sqrt{29}$

Hence, the statement proves that quadrilateral HIJK is a kite is IH = IJ = 3 and JK = HK = $\sqrt{29}$ and IH ≠ JK and IJ ≠ HK.

To know more about quadrilateral click the link given below.

brainly.com/question/1751208

3 0

2 years ago

Read 2 more answers

F(x)= x sqrt(x + 4)

notka56 [123]

$F(x)=x \sqrt{x+4}
\\
\\ F'(x)=(x \sqrt{x+4})'=\sqrt{x+4}+ \frac{x}{2 \sqrt{x+4} } 
\\
\\F'(x)=0
\\
\\ \sqrt{x+4}+ \frac{x}{2 \sqrt{x+4} } =0
\\
\\ \frac{2(x+4)}{2 \sqrt{x+4} }+\frac{x}{2 \sqrt{x+4} } =0
\\
\\\frac{3x+8}{2 \sqrt{x+4} } =0
\\
\\3x+8=0
\\x=- \frac{8}{3} 
\\ x\in(-\infty,- \frac{8}{3} )\Rightarrow y\downarrow
\\ x\in(- \frac{8}{3},+\infty )\Rightarrow y\uparrow$

$F''(x)=(\frac{3x+8}{2 \sqrt{x+4} })'= \frac{3\times2\sqrt{x+4}- \frac{3x+8}{ \sqrt{x+4} } }{4(x+4)} = \frac{6(x+4)-(3x+8)}{4(x+4)\sqrt{x+4}} =
 \frac{3x+16}{4(x+4)\sqrt{x+4}} 
\\
\\F''(x)=0
\\
\\ \frac{3x+16}{4(x+4)\sqrt{x+4}} =0
\\
\\3x+16=0
\\
\\x=- \frac{16}{3} 
\\
\\x\in(-\infty,- \frac{16}{3})\cup(-4,+\infty)\Rightarrow F''(x) > 0\Rightarrow \text{ F(x) concave up}$

3 0

3 years ago

Your family vacation involves a cross-country air flight, a rental car, and a hotel stay in boston. if you can choose from three

Diano4ka-milaya [45]

We can solve problems like this using multiplication rules. Since the order of accommodations does not matter, we can multiply all numerical values in any order we so choose. In this case, our numerical values are three air carriers, two car agencies, and five hotels.

3 x 2 x 5 = 30

There are 30 options available for vacation accommodations.

7 0

3 years ago

How do you divide 9,962 and 41 how do you divide 909900 + 62 + 41

7nadin3 [17]

242.975609756 I don't know about the last one though.

5 0

3 years ago