4y + 12 = -3x - 16<br> Write an equation in slope-intercept form.

prohojiy [21]

Answer:

x=2.8

Step-by-step explanation:

If JKLMN and PQRST are similar then you can look the to other sides to find the ratio that relates the two. For this specific one you are able to fin 0.4 is the relationship.

NJ is related to TP by a factor of 1.4. -> NJ*1.4=TP -> 4*1.4=5.6

The rest can be said to relate all the other sides together.

8 0

3 years ago

Find c to the nearest 10th. (laws of sines)

elena55 [62]

Answer:

Option D

Step-by-step explanation:

By applying cosine rule in the given triangle,

a² = b² + c² - 2b.c.cos(m∠A)

By substituting values in the formula,

9² = 10² + c² - 2(10)(c)cos(15)°

81 = 100 + c² - 19.32c

c² - 19.31c + 19 = 0

By quadratic formula,

c = $\frac{19.31\pm\sqrt{(19.31)^{2}-4(1)(19)}}{2(1)}$

= $\frac{19.31\pm17.23}{2}$

= 1.08, 18.27

≈ 1.1, 18.3

Therefore, Option D will be the answer.

8 0

3 years ago

A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the

juin [17]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the commercial improved the mean purchase potential rating.

Step-by-step explanation:

If we calculate the difference in ratings we have:

After Before Difference

1 6 -5

5 2 3

6 4 2

3 7 -4

7 4 3

4 3 1

5 3 2

5 6 -1

9 8 1

7 7 0

5 8 -3

6 6 0

We will calculate the mean and standard deviation of the difference to test them later.

The sample size is n=12.

The mean is:

$M=\dfrac{1}{12}\sum_{i=1}^{12}((-5)+3+2+(-4)+3+1+2+(-1)+1+0+(-3)+0)\\\\\\ M=\dfrac{-1}{12}=-0.083$

The standard deviation is:

$s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{12}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{11}\cdot [(-5-(-0.083))^2+(3-(-0.083))^2+...+(0-(-0.083))^2]}\\\\\\$

$s=\sqrt{\dfrac{1}{11}\cdot [(24.17)+(9.51)+...+(1.17)+(0.01)+(8.51)+(0.01)]}\\\\\\s=\sqrt{\dfrac{78.92}{11}}=\sqrt{7.174}\\\\\\s=2.678$

The null hypothesis states that the mean rating "after" would be less than or equal to the mean rating "before." The alternative hypothesis states that the mean rating difference is greater than 0.

Then, the null and alternative hypothesis:

$H_0: \mu\leq0\\\\H_a:\mu> 0$

The significance level is 0.05.

The sample has a size n=12.

The sample difference is d=-0.083.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.678.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2.678}{\sqrt{12}}=0.773$

Then, we can calculate the t-statistic as:

$t=\dfrac{\bar d}{s/\sqrt{n}}=\dfrac{-0.083}{0.773}=-0.108$

The degrees of freedom for this sample size are:

$df=n-1=12-1=11$

This test is a right-tailed test, with 11 degrees of freedom and t=-0.108, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>-0.108)=0.542$

As the P-value is greater than the significance level, the effect is not significant. The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the commercial improved the mean purchase potential rating.

5 0

3 years ago

a pair of in-line skates regular regular price at 180 is now on sale at 8:30 percent discount what is the sales price of the ska

nikklg [1K]

What percent discount?

6 0

3 years ago

Find the equation of a line with slope −2 that passes through the point (−1, 6).

Gnesinka [82]

Answer:

y = -2x + 4

Step-by-step explanation:

y = mx + b

(plug in slope)

y = -2x + b

(plug in point they provide)

6 = -2(-1) + b

6 = 2 + b

b = 4

y = -2x + 4

7 0

3 years ago

4y + 12 = -3x - 16 Write an equation in slope-intercept form.