Question

3. Volunteer drivers are needed to bring 80 students to the championship baseball

Answer 1

Answer:

Options (B), (C) and (E) are the correct options.

Step-by-step explanation:

Equation that represents relation between the number of cars c and the number of vans v to transport 80 students is,

4c + 6v = 80

Option A.

If c = 12,

4(12) + 6(v) = 80

48 + 6v = 80

6v = 32

$v=\frac{16}{3}$

Which is not equal to 2.

Therefore, Option A is incorrect.

Option B

If c = 14,

4(14) + 6(v) = 80

56 + 6v = 80

6v = 24

v = 4

Therefore, c = 14 and v = 4 is a pair of solutions.

Option B is correct.

Option C.

If c = 6 and v = 11

4(6) + 6(11) = 24 + 66

                 = 90

This means with 6 cars and 11 vans 90 students can be transported. Therefore, there will be extra space.

Option C is correct.

Option D.

If c = 10 and v = 8

4(10) + 6(8) = 40 + 48

                  = 88

Therefore, 10 cars and 8 vans are enough to transport 80 students.

So option D is incorrect.

Option E.

If c = 20,

4(20) + 6(v) = 80

80 + 6v = 80

v = 0

Therefore, for 20 cars go no vans are needed.

Option E is correct.

Option F.

Constraints in this situation,

Minimum number of cars to be used = 20

c ≥ 20

Minimum number of vans to be used = $\frac{80}{6}$ ≈ 14

v ≥ 14

Therefore, Option (F) is incorrect.