Question

What is the missing coefficient of the x-term of the product (–x – 5)2 after it has been simplified?

Answer 1

we have

$(-x-5)^{2}$

we know that

$(-x-5)^{2}=(-x-5)*(-x-5)$

To multiply two binomial I can use the FOIL method

$(-x-5)*(-x-5) =(-x)*(-x)+(-x)*(-5)+(-5)*(-x)+(-5)*(-5)\\ =x^{2} +5x+5x+25\\ =x^{2} +10x+25$

therefore

the answer is

the missing coefficient of the x-term is $10$

Answer 2

the missing coefficient of the x-term of the product (–x – 5)2 after it has been simplified is the below:

(–x – 5)2 = x2 + 10x + 25

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