In finding the minimum amount of time that Brandon can swim is to add the quotient of the distance to swim and its velocity and the quotient of the difference of 250 and the distance cover in running and its velocity. The minimum time is 43.33 seconds
3 miles each day for x days is 3x
5 miles each day for y days is 5y
Frank ran at least as many miles as Latoya is 3x >/= 5y
Answer:
sample mean:: 17.92
ME = z*s/sqrt(n) = 1.8807*6.35/sqrt(47) = 1.7421
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Step-by-step explanation:
The answer would be A Im Sure If not I apologize
Soo 100.26-15% off = $85.25 and 59.99 you need to crank it up 1 so $60-10% off=$54 last add $85.25+$54=$129.25
So no she is not right
