Answer:
wait so what is the numbers of distance they have swam?
Step-by-step explanation:
r = radius
Arc length = 2(3.14)r
7.9 cm = r
Plug our values in
Arc length = 2(3.14)(7.9 cm)
Arc length = 49.6 cm
Answer:
39 units²
Step-by-step explanation:
Quadrilateral VEDR has a width of 5 units and a height of 6 units, so an area of ...
(5 units)(6 units) = 30 units²
Triangle MVR has a base (VR) of 6 units and a height (M to VR) of 3 units, so an area of ...
(1/2)(6 units)(3 units) = 9 units²
Then the total area of the polygon MVEDR is ...
30 units² +9 units² = 39 units²
Answer:
<h3>132°</h3>
Step-by-step explanation:
If line PS has midpoint a Q and ray QR, then line PQS will be a straight line and <PQR + <RQS = 180 (sum of angle on a straight line).
Given
<PQR = 3x-6
<RQS = x+ 2
To get x, we will use the relationship above;
3x-6+x+2 = 180
4x-4 = 180
add 4 to both sides
4x-4+4 = 180+4
4x = 184
x = 184/4
x = 46
Since <PQR = 3x-6, we will substitute the value of x into the formula;
<PQR = 3x-6
<PQR = 3(46)-6
<PQR = 138-6
<PQR = 132°
Hence the size of angle PQR is 132°
The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
</span>
So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
</span>
<span>=====================================================
</span>
<span>Another solution:
</span>
<span>If ann seated in one of the ends, the number of ways = 3*2
</span>
<span>If ann didn't seat in one of the ends , the number of ways = 2*3
</span>
So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
</span></span>
The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72