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erica [24]
1 year ago
11

lect the correct answer from the list. (1 point) the expression that is being taken. m represents the Select Answers to which I

is raised, and n represents the Select Answer Select Answer radicant numerator root power
Mathematics
1 answer:
jolli1 [7]1 year ago
5 0

Given:

x^{\frac{m}{n}}

The expression can be used to express powers and roots together.

Here, we can rewrite this as:

x^{\frac{m}{n}}=\sqrt[n]{x^m}\text{ = (}\sqrt[n]{x})^m

Here, m is the power while n is the root.

Therefore, m represents the power to which x is raised while n represents the root that is being taken.

ANSWER:

Power; Root

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2y+3=11<br> two y add three = 11
sveticcg [70]

Answer:

 y=4.5

Step-by-step explanation:

2y+3=11

2y=11-3

2y=9

y= 4.5

7 0
2 years ago
If you deposited a penny on May 1st and doubled what you deposited each day for a month, how many pennies would you be depositin
PIT_PIT [208]

Answer:

30

Step-by-step explanation:

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3 years ago
Simplify to an expression of the form (a sin(θ)).<br> 2sin(/8)2cos(/8)
rjkz [21]

Answer:

Your expression equals 2 \sin(\frac{\pi}{4}) assuming the problem was to simplify 2\sin(\frac{\pi}{8}) 2\cos(\frac{\pi}{8}) to the form a\sin(\theta).

Step-by-step explanation:

2\sin(\frac{\pi}{8}) 2\cos(\frac{\pi}{8})

2(2)\sin(\frac{\pi}{8})\cos(\frac{\pi}{8})

Let's use the following identity: 2\sin(A)\cos(A)=\sin(2A)

2\sin(2 \cdot \frac{\pi}{8})

2 \sin(\frac{\pi}{4}) which is comparable to the form a\sin(\theta).

a=2

\theta=\frac{\pi}{4}

5 0
3 years ago
First try was incorrect
SIZIF [17.4K]

Answer:b

Step-by-step explanation:

3 0
3 years ago
What operations would Addison perform, and in what order would Addison perform them, to solve 5n+ 15 = 20 ?
Minchanka [31]
I think it’s C because 5n means multiplying both integers
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3 years ago
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