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Mrac [35]
3 years ago
14

Bethanie's daily drive to work involves driving through some steep terrain. She came up with the following graph to model her el

evation, in feet above sea level, t minutes into her daily commute to work. Mike also decided to create a function to model his elevation, in feet from sea level, t minutes into his daily commute to work. The function is shown below. M(t)=x^3-6x^2+11x-6 If Bethanie and Mike both take eight minutes to drive to work, which person drives to the higher elevation? A. Both Bethanie and Mike drive the same distance above sea level. B. Bethanie C. This cannot be determined from the given information. D. Mike

Mathematics
2 answers:
shtirl [24]3 years ago
8 0

Answer:

Option D.

Step-by-step explanation:

-If the attached graph shows the distance above sea level to which Bethanie's leads as a function of time, then we can observe that after having elapsed 8 minutes Bethanie's is a distance of 0 from sea level.

The graph shows that the value of B(t) is always less than 1 during the 8 minutes of travel.

-On the other hand, the function M(t) = t ^ 3-6t ^ 2 + 11t-6 that models the distance above sea level that Mike drives as a function of time, shows us that after 3 minutes the distance M(t) begins to increase rapidly until at t = 8 minutes:

M(t) = 8 ^ 3 -6 (8) ^ 2 +11 (t) -6 = 210.

Therefore the correct option is D

The person who leads to the highest elevation is Mike.

liberstina [14]3 years ago
7 0

Answer:

for plato users its b

Step-by-step explanation:

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Alexandra [31]

The simplified form of R(x) is R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}

<h3>Simplifying an expression </h3>

From the question, we are to simplify the expression

From the given information,

f(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30}

and

g(x) =\frac{x^{2}-9x+20 }{x^{2}-12x+36}

Also,

R(x) = f(x) \div g(x)

∴ R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \div \frac{x^{2}-9x+20 }{x^{2}-12x+36}

R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \times \frac{x^{2}-12x+36 }{x^{2}-9x+20}

Factoring each of the quadratics

R(x) =\frac{x^{2}-7x-4x+28 }{x^{2}-6x-5x+30} \times \frac{x^{2}-6x-6x+36 }{x^{2}-4x-5x+20}

R(x) =\frac{x(x-7)-4(x-7) }{x(x-6)-5(x-6)} \times \frac{x(x-6)-6(x-6) }{x(x-4)-5(x-4)}

R(x) =\frac{(x-4)(x-7)}{(x-5)(x-6)} \times \frac{(x-6)(x-6)}{(x-5)(x-4)}

Simplifying

R(x) =\frac{(x-7)}{(x-5)} \times \frac{(x-6)}{(x-5)}

R(x) =\frac{(x-7)(x-6)}{(x-5)(x-5)}

R(x) =\frac{x^{2} -6x-7x+42}{x^{2} -5x-5x+25}

R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}

Hence, the simplified form of R(x) is R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}

Learn more on Simplifying an expression here: brainly.com/question/1280754

#SPJ1

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