Answer: See below
Step-by-step explanation:




Simplify:

Answer:
The likelihood that the professor's socks matched his pants on both days is 0.5625
Step-by-step explanation:
Total no. of pair of socks = 24
No. of black pairs = 18
We are given that he selects one pair of socks on Monday and one on Tuesday. Since he has lots of clean socks in the drawer he does not do laundry.
So, It is a case of replacement
He always wears black pants.
We are supposed to find he likelihood that the professor's socks matched his pants on both days i.e. Black socks both days.
So ,Probability of wearing black socks on Monday = 
So ,Probability of wearing black socks on Tuesday =
So,the likelihood that the professor's socks matched his pants on both days = 
Hence the likelihood that the professor's socks matched his pants on both days is 0.5625
Answer:
P = 0.4812
Step-by-step explanation:
First, we need to use here two expressions and then do the calculations.
The first one is the conditional probability which is:
P(B|A) = P(A∩B)/P(A) (1)
The second expression to use has relation with the Bayes's theorem which is the following:
P(D|C) = P(C|D)*P(D) / P(C|D)*P(D) + P(C|d)*P(d) (2)
Now, the expression (2) is the one that we will use to calculate the probability of a selected random bicyclist who tests positive for steroids.
So, in this case, we will call C for positive and D that is using steroids and d is the opposite of d, which means do not use steroids.
Then, the probabilities are the following:
P(D) = 8% or 0.08
P(C|D) = 96% or 0.96
P(C|d) = 9% or 0.09
P(d) = 1 - 0.08 = 0.92
With these data, let's replace in expression 2
P(D|C) = 0.96 * 0.08 /0.96 * 0.08 + 0.09*0.92
P(D|C) = 0.0768 / 0.1596
P(D|C) = 0.4812 or 48.12%
Step-by-step explanation:
Answer:
482895ft^2
Step-by-step explanation:
Given data
Width= 657ft
Length= 735ft
We know that area A
A= Length* Width
A=657*735
A= 482895ft^2
Hence the area is 482895ft^2