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denis-greek [22]
2 years ago
8

EASY I AM JUST DUMB!! WILL GIVE BRANLIEST!!! HELP ASAP!!!!

Mathematics
1 answer:
Dominik [7]2 years ago
7 0

Answer:

D

Step-by-step explanation:

altitude is always perpendicular to base

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Simplify: 113 ÷ 113 · 113 112 113 116 119
Sergeeva-Olga [200]

Answer: 113

Step-by-step explanation: 113/113=1(113) =113

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3 years ago
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What will it cost to buy a rectangular window with a length of 10ft and a width of 13ft? The cost per square foot for this type
Bad White [126]

Answer:i need points

Step-by-step explanation:

4 0
3 years ago
Evaluate the integral. W (x2 y2) dx dy dz; W is the pyramid with top vertex at (0, 0, 1) and base vertices at (0, 0, 0), (1, 0,
In-s [12.5K]

Answer:

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

Step-by-step explanation:

Given that:

\iiint_W (x^2+y^2) \ dx \ dy \ dz

where;

the top vertex = (0,0,1) and the  base vertices at (0, 0, 0), (1, 0, 0), (0, 1, 0), and (1, 1, 0)

As such , the region of the bounds of the pyramid is: (0 ≤ x ≤ 1-z, 0 ≤ y ≤ 1-z, 0 ≤ z ≤ 1)

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 \int ^{1-z}_0 (x^2+y^2) \ dx \ dy \  dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 ( \dfrac{(1-z)^3}{3}+ (1-z)y^2) dy \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^3}{3} \ y + \dfrac {(1-z)y^3)}{3}] ^{1-x}_{0}

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^4}{3}+ \dfrac{(1-z)^4}{3}) \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =\dfrac{2}{3} \int^1_0 (1-z)^4 \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =- \dfrac{2}{15}(1-z)^5|^1_0

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

7 0
3 years ago
\frac{3}{10} = \frac{x}{x + 2}​10​​3​​=​x+2​​x​​
a_sh-v [17]
7 because the way its set up
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3 years ago
What is the Absoulte value of 3
aleksandr82 [10.1K]

Answer:

it's 3

Step-by-step explanation:

Number 3 is 3 units away from 0, and thus the absolute value of 3 is 3.

3 0
2 years ago
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