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Mrac [35]
3 years ago
5

How is solving a problem about constant speed similar to solving a problem about unit price?

Mathematics
1 answer:
DochEvi [55]3 years ago
6 0
Unit price means divide. And a speeding is a problem that you do in class.
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Explain how to find the absolute value of an interger
S_A_V [24]
The absolute value of an integer is the distance from zero. So, another way of thinking of is to ignore positive or negative. for example the absolute value of -126 is 126, same would go for positive 126.
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3 years ago
Nine subtracted from the product of 4 and a number is greater than -19
krok68 [10]

Answer:What’s the question-

Step-by-step explanation:9-4 and greater than -19? Oh 5 because 9-4=5 but it’s greater than -19 because -19 is a negative number.

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2 years ago
I need help with question 5 show your work.Also tell me if my divison for question 6 is correct.Thx.P.S.I Will give the brainlie
Sloan [31]
5. Start by finding how many tiles make up the outer edge of the pool. We know that each tile is 3/4 foot, and that the entire length is 12 feet. So by doing a division, we'll find how many tiles there are:
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3 years ago
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Which property of multiplication is shown?<br><br> 9 × 0 − 6 × 0 = (9 − 6) × 0
JulsSmile [24]

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3 years ago
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Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
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