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4 years ago

11

Angela opened a new bakery. She got orders for 2 cakes the first week, 4 cakes the second week, and 8 cakes the third week. If t

he pattern continue how
many cakes orders she get the fourth week ?

1 answer:

Morgarella [4.7K]4 years ago

3 0

Answer: 16 cakes.

From the pattern of 2,4,8 we can see that each week the amount of cakes ordered doubles. If we apply that same logic, we will get 8 + 8 = 16.

- Hope it helps!

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Answer:

$\large\boxed{\boxed{x = \begin{cases} \frac{ \sqrt{3} }{2} + 2 \\ - \frac{ \sqrt{3} }{2} + 2 \end{cases}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic equation
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<h3>let's solve:</h3>

$\sf divide \: both \: sides \: by \: 12 : \\ \sf {x}^{2} - 4x = - \frac{13}{4}$
$\sf \: add \: { - 2}^{2} \: to \: both \: sides : \\ \sf { {x}^{2} } - 4x + ( - {2}^{2} ) = \frac{13}{4} + ( { - 2}^{2} ) \\ {x}^{2} - 4x + 4 = \frac{13}{4} + 4$
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$\sf use \: {a}^{2} - 2ab + {b}^{2} = (a - b {)}^{2} : \\ \sf (x - 2 {)}^{2} = \frac{3}{4}$
$\sf squre \: root \: both \: sides : \\ \sf \sqrt{(x - 2 {)}^{2} } = \pm \sqrt{ \frac{3}{4} } \\ \begin{cases} x - 2 = \frac{ \sqrt{3} }{2} \\x - 2 = - \frac{ \sqrt{3} }{2} \end{cases}$
$\sf add \: 2 \: to \: both \: sides : \\ \sf \begin{cases}x = \frac{ \sqrt{3} }{2} + 2 \\ x = - \frac{ \sqrt{3} }{2} + 2 \end{cases} \\ \therefore \: x = \begin{cases} \frac{ \sqrt{3} }{2} + 2 \\ - \frac{ \sqrt{3} }{2} + 2 \end{cases}$

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Step-by-step explanation:

Given

$\log 8 - \log x + 7\log\sqrt x$

Required

Express as a single expression

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$\log 8 - \log x + 7\log\sqrt x$

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$\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(\sqrt x)^7$

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$\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(x^{\frac{1}{2}})^7$

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$\log 8 - \log x + 7\log\sqrt x =\log (\frac{8*x^\frac{7}{2}}{x} )$

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$\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7}{2} - 1})$

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$c + 72 = h$
$253 + 72 = h$
$325 = h$
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