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3 years ago

Which of the following equations is an example of the Associative Property of Addition?

Mathematics

1 answer:

user100 [1]3 years ago

8 0

Answer:

Option B) (5+6)+4=5+(6+4) is correct

An example of the associative property of addition is (5+6)+4=5+(6+4)

Step-by-step explanation:

Given $(5+6)+4=5+(6+4)\hfill (1)$

Verify that the given equation is an example of associative property of addition or not:

We have the associative property of addition

$(a+b)+c=a+(b+c) \hfill (2)$

Comparing the equation (1) and(2) we have the given equation is in associative property

Therefore option B) (5+6)+4=5+(6+4) is correct

An example of the associative property of addition is (5+6)+4=5+(6+4)

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one angle of a triangle is 2 / 3 of a right angle . the greater of the other to exceed the lesser by 20 degree. Find the angles

jarptica [38.1K]

2/3 of a right triangle is 60 degrees. Then x + (x+20) + 60 = 180 total.

2x + 80 = 180, so 2x = 100 and x = 50. The angles are 50, 70 and 60 (degrees)

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3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago

You have a pool that measures 8 yards by 10 yards. You want to build a deck around all four sides of the pool and you want to in

gladu [14]

Given:
pool length : 10 yards
pool width : 8 yards

Area = 10 yds * 8 yds = 80 yd²

(10 + 2x)(8 + 2x) = 120
10(8 + 2x) + 2x(8+2x) = 120
80 + 20x + 16x + 4x² = 120
4x² + 36x + 80 - 120 = 0
4x² + 36x - 40 = 0
4(x² + 9x - 10) = 0
4(x + 10)(x - 1) = 0

x + 10 = 0
x = -10
x - 1 = 0
x = 1

the width of the deck is 1 yard

7 0

3 years ago

A rectangle with an area of 5/8 ft² is dilated by a factor of 8. What is the area of the dilated rectangle?

gulaghasi [49]

Answer:

40 ft²

Step-by-step explanation:

Let the length of the original rectangle be L and original Breadth be B

it is given that the original area is 5/8 ft²

i.e.

Original Length x Original Breadth = Original Area, or,

LB = 5/8 ft² ------------------(1)

Given that the dilation factor is 8,

Hence,

New Length = 8L and New Breadth = 8B

THerefore,

New Area = 8L x 8B

= 64 LB (from (1) above , we know that LB = 5/8 ft², substitute into expression)

= 64 (5/8)

= 40 ft²

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4 years ago

What is the absolute value of 0

Ainat [17]

The absolute value of zero is zero

5 0

3 years ago

Read 2 more answers