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Vesnalui [34]
3 years ago
15

A parallelogram has sides 17.3 m and 43.4 m long. The height corresponding to the 17.3-m base is 8.7 m. Find the height, to the

nearest tenth of a meter, corresponding to the 43.4-m base.
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

3.5m

Step-by-step explanation:

A parallelogram has sides 17.3 m and 43.4 m long.

The height corresponding to the 17.3-m base is 8.7 m.

The area of a parallelogram = base × height

= 8.7m × 17.3m

= 150.51m²

Both parallelograms have the same area

Hence, the height, to the nearest tenth of a meter, corresponding to the 43.4-m base is calculated as:

= 150.51m²/43.4m

= 3.4679723502m

Approximately = 3.5m

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Answer:

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Step-by-step explanation:

A way to set an equation up for this problem is:

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where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

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Don’t solve the whole equation, just solve the \frac{4}{3}(18) part of the equation, which is equal to 24. So the final equation is this:

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Sorry for the long explanation.

But hope this helps and answers your question :)

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