Answer:
Answered below.
Explanation:
The three general methods consist of unicasting, broadcasting and multicasting.
Casting implies the transfer of data from one computer (sender) to another (recipient).
Unicasting is the transfer of data from a single sender to a single recipient.
Broadcasting deals with the transfer of data from one sender to many recipients.
Multicasting defines the transfer of data from more than one sender to more than one recipients.
I'm a little confused about the question, but if you're asking how many points you need to ask a question, the minimum is 10.
The publisher tab in the application control allows you to manage the various certificates that are used to sign to binaries. Publisher allow executables of a particular vendor, signed by a security certificate issued
to the vendor by a Certificate Authority. Also, all applications and binary files either added
to or modified on an endpoint that are signed by the certificate are automatically added to
the whitelist.
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) =
=
= 0.0316
For x = 120, sample proportion(p) =
=
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z <
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Keyboard-Input
Mouse-Input
<u></u>Monitor-Output
Speakers-Output
Printer-Output
Hard Drive<span>-Output</span>