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stepan [7]
3 years ago
14

Write the definitions for three functions named max. Each receives two parameters, of the same type, and returns the larger of t

he two values. Define one of these functions to apply to type double, another to type int and a third to type char.
Computers and Technology
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

public double max(double m, double n)

{

if (m>=n)

return m;

else

return n;

}

public int max(int m, int n)

{

if (m>=n)

return m;

else

return n;

}

public char max(char m, char n)

{

if (m>=n)

return m;

else

return n;

}

Explanation:

In each of the three methods declarations (Java) above, we are comparing two variables. m and n. The question did not specify what should happen when both variables are the same (i.e. m = =n). We make an assumption and set the condition to be if(m>=n) m should be returned as the greater.

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. (a) Prove or disprove carefully and in detail: (i) Θ is transitive and (ii) ω is transitive. (b) Assume n is a positive intege
Sergio [31]

Answer:

The Following are the solution to this question:

Explanation:

In Option a:

In the point (i) \Omega is transitive, which means it converts one action to others object because if \Omega(f(n))=g(n) indicates c.g(n). It's true by definition, that becomes valid. But if \Omega(g(n))=h(n), which implies c.h(n). it's a very essential component. If c.h(n) < = g(n) = f(n) \. They  \Omega(f(n))   will also be h(n).  

In point (ii), The  value of \Theta is convergent since the \Theta(g(n))=f(n). It means they should be dual a and b constant variable, therefore a.g(n) could only be valid for the constant variable, that is  \frac{1}{a}\ \  and\ \ \frac{1}{b}.

In Option b:

In this algorithm, the input size value is equal to 1 object, and the value of  A is a polynomial-time complexity, which is similar to its outcome that is O(n^{2}). It is the outside there will be a loop(i) for n iterations, that is also encoded inside it, the for loop(j), which would be a loop(n^{2}). All internal loops operate on a total number of N^{2} generations and therefore the final time complexity is O(n^{2}).

6 0
3 years ago
Fill in the blanks, so the print statement displays the result of the function call in order.
sergejj [24]

Answer:

Rep;ace the blank with

smaller, bigger

So, the complete line is:

smaller,bigger=order_numbers(100,99)

Explanation:

From the question, we understand that the program is to return the order of a number from least to highest

This has been well implemented in order_numbers function

Because the order function returns two values, the order_function must be called in order to accept two values and the syntax is:

<em>value1,value2 = function(return-value1,return-value2)</em>

In this case, the statement is:

smaller,bigger=order_numbers(100,99)

So, in the next line of the main, the values of smaller and bigger are printed:

<em>print(smaller,bigger)</em>

See attachment

Download txt
8 0
3 years ago
Sheila is using a process of saving files to her desktop and then renaming them. She is
inessss [21]

Answer: D

Use the internet to search for a new app to rename the folder.​

Explanation:

Rename function is used to change the name of the file or directory i.e. from old_name to new_name without changing the content present in the file. This function takes name of the file as its argument. There are many alternatives to this in which Sheila can found out through the internet.

5 0
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Simora [160]

Answer:

One benefit for a small business using the hosted software model for its enterprise software is that it can succeed without employing full-time IT professionals.

Explanation:

7 0
2 years ago
How can I put my keyboard back​
zvonat [6]

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~

8 0
3 years ago
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