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stepan [7]
3 years ago
14

Write the definitions for three functions named max. Each receives two parameters, of the same type, and returns the larger of t

he two values. Define one of these functions to apply to type double, another to type int and a third to type char.
Computers and Technology
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

public double max(double m, double n)

{

if (m>=n)

return m;

else

return n;

}

public int max(int m, int n)

{

if (m>=n)

return m;

else

return n;

}

public char max(char m, char n)

{

if (m>=n)

return m;

else

return n;

}

Explanation:

In each of the three methods declarations (Java) above, we are comparing two variables. m and n. The question did not specify what should happen when both variables are the same (i.e. m = =n). We make an assumption and set the condition to be if(m>=n) m should be returned as the greater.

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Write a program that calculates the occupancy rate for ahotel. The program should start by asking the user how many floorsthe ho
Oksana_A [137]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

using namespace std;   //to identify objects like cin cout

int main(){  //start of main function

       int MinFloors = 1;  //minimum number of floors

       int MinRooms  = 10; //minimum number of rooms

       int NoOfFloors;  //stores number of floors

       int NoOfRooms;  //stores number of rooms

       int OccupiedRooms;  //stores number of rooms occupied

       double TotalRooms=0, TotalOccupied=0;   //stores computed total number of rooms and total number of occupied rooms

       cout<<"How many floors does the hotel have? ";  //prompts user to enter number of floors

       do{  //iterates until the user enters valid number of floors

           cout<<"(cannot be less than "<<MinFloors<<"): ";  //error message

           cin >>NoOfFloors;  //reads number of floors from user

       }while(NoOfFloors<MinFloors);  //repeats as long as number of floors is less than minimum number of floors

       for(int floor=1; floor <= NoOfFloors; floor++){    //iterates through the floors to skip third iteration

           if(floor == 3){   //if floor is third floor

               continue;             }  

           cout<<"How many rooms are on floor " <<floor;  //prompts user to enter number of floors

           do{  //start of do while loop

               cout<<"(cannot be less than "<<MinRooms<<"): ";  //error message

               cin >>NoOfRooms;  //reads number of rooms from user

           }while(NoOfRooms<MinRooms);    //iterates as long as number of rooms are less than valid minimum number of rooms

           TotalRooms += NoOfRooms;   //adds number of rooms to the count of total number of rooms

           cout<<"How many of those rooms are occupied?";  //prompts user to enter number of rooms occupied

           do{  //start of do while loop

         cout<<"(cannot be less than 0 or greater than "<<NoOfRooms<<"): ";  //generates error message

         cin >>OccupiedRooms;  //reads number of rooms occupied by user

           }while(OccupiedRooms<0 || OccupiedRooms>NoOfRooms);   //iterates as long as the number of occupied rooms are less than 0 or greater than number of rooms

           TotalOccupied += OccupiedRooms;    }    //adds number of rooms occupied to the count of total number of occupied rooms    

       cout<<"\nThe hotel has a total of "<<TotalRooms<<" rooms"<<endl;  //displays the total number of rooms in the hotel

       cout<<TotalOccupied<<" are occupied."<<endl;  //displays the total number of occupied rooms

       cout<<(TotalRooms-TotalOccupied)<<" are unoccupied."<<endl;  //displays the total number of unoccupied rooms

cout<<"The occupancy rate is: "<<100*(TotalOccupied/TotalRooms)<<"%"<<endl;     }  //computes and displays the occupancy rate

   

Explanation:

The program first prompts the user to enter number of floors in the hotel. Lets say user enters 6. This is stored in NoOfFloors So

NoOfFloors = 6

So the loop runs for 6 times

Next it asks user to enter the number of rooms in the floor 1. Lets say user enters 12 so this is stored in NoOfRooms so

NoOfRooms = 12

TotalRooms += NoOfRooms;

this statement keeps adding number of rooms to TotalRooms so

TotalRooms = 12

Next program asks user about the number of occupied rooms. Lets say user enters 10 so this is stored in OccupiedRooms so

OccupiedRooms = 10

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10

At next iteration program asks user again to enter number of rooms in floor 2. Suppose user enters 14 so

NoOfRooms = 12

TotalRooms += NoOfRooms;

TotalRooms = 12+14

TotalRooms = 26

Program asks again to enter number of occupied rooms so it becomes:

OccupiedRooms = 8

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10+8

TotalOccupied = 18

Next is skips floor 3 and iteration 3. and asks user to enter number of rooms in floor 4. Suppose user enters 14

Number of rooms become:

TotalRooms = 12+14+14

TotalRooms = 40

and suppose user enters 14 as occupied rooms so total occupied become:

TotalOccupied = 10+8 + 14

TotalOccupied = 32

For floor 5: Suppose user enters 13

TotalRooms = 12+14+14+13

TotalRooms = 53

For floor 5: Suppose user enters 10

TotalOccupied = 10+8 + 14+10

TotalOccupied = 42

For floor 6: Suppose user enters 12

TotalRooms = 12+14+14+13+12

TotalRooms = 65

For floor 6: Suppose user enters 11

TotalOccupied = 10+8 + 14+10+11

TotalOccupied = 53

Now the loop breaks

Hence

TotalRooms = 65

TotalOccupied  = 53

total unoccupied = TotalRooms-TotalOccupied = 65-53 = 12

The occupancy rate is: 100*(TotalOccupied/TotalRooms) = 100*(53/65) = 81.5385

The output of the program is attached in a screenshot.

6 0
3 years ago
Timur was making a presentation regarding how attackers break passwords. His presentation demonstrated the attack technique that
kakasveta [241]

Answer:

The answer of the following question is Brute force attack .

Explanation:

A brute force attack is the error and trial method that is used by an application program to decode the encrypted data like passwords or the Data Encryption Standard (DES) keys, which through an exhaustive effort (by using brute force) rather than the employing an intellectual strategies.

7 0
2 years ago
The following problem illustrates the way memory aliasing can cause unexpected program behavior. Consider the following function
laila [671]

Answer:

A

Explanation:

The value will be the original stored in the int variables. This is because the method swap(int xp, int yp) accepts xp and yp parameters by value (They are passed by value and not by reference). Consider the implementation below:

public class Agbas {

   public static void main(String[] args) {

   int xp = 2;

   int yp = xp;

   swap(xp,yp); //will swap and print the same values

       System.out.println(xp+", "+yp); // prints the original in values 2,2

 int xp = 2;

   int yp = 5;

   swap(xp,yp); // will swap and print 5,2

       System.out.println(xp+", "+yp); // prints the original in values 2,5

   }

   public static void swap(int xp, int yp){

       int temp = xp;

       xp = yp;

       yp = temp;

       System.out.println(xp+", "+yp);

   }

}

5 0
3 years ago
Suppose a computer has 16-bit instructions. The instruction set consists of 32 different operations. All instructions have an op
Kazeer [188]

Answer:

2^7= 128

Explanation:

An instruction format characterizes the diverse part of a guidance. The fundamental segments of an instruction are opcode and operands. Here are the various terms identified with guidance design:  Instruction set size tells the absolute number of guidelines characterized in the processor.  Opcode size is the quantity of bits involved by the opcode which is determined by taking log of guidance set size.  Operand size is the quantity of bits involved by the operand.  Guidance size is determined as total of bits involved by opcode and operands.

6 0
3 years ago
What is the basic process of programming?
NikAS [45]

Answer:

There are usually three stages to writing a program: Coding. Compiling. Debugging.

8 0
2 years ago
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