A = P(1 + r/n)^(nt)
<span>A = 7300(1 + 0.07/2)^(2)(3) = 7300(1.035)^6 = 7300(1.2293) = $8973.56 </span>
<span>A = 2100(1 + 0.094/4)^(4)(2) = 2100(1.0235)^8 = 2100(1.2042) = $2528.84 </span>
10(length) by 6.5(width). 6.5×2=13, 13-3=10
Then you don’t get lost doing the problem
(357) the 3 is in the hundredth place, the 5 is in the tens place and the 7 is in the ones place
