ANSWER
The value of theta in the second quadrant is,
EXPLANATION
The given trigonometric equation is
This implies that,
This implies that the principal solution is
and it is an angle in the first quadrant.
But the solution we are looking for is an angle in the second quadrant.
This is given by
Answer:
Part 1)
Bob's mistake was to have used the cosine instead of the sine
The measure of the missing angle is 
Part 2) The surface area of the pyramid is 
Step-by-step explanation:
Part 1)
Let
x----> the missing angle
we know that
In the right triangle o the figure
The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle
Bob's mistake was to have used the cosine instead of the sine
Part 2) we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
where
b is the length side of the square
h is the height of the triangular lateral face
In this problem
-------> by an 45° angle
so
Find the value of b
Find the surface area
![SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}](https://tex.z-dn.net/?f=SA%3D12%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2812%29%286%29%5D%3D288%5C%20cm%5E%7B2%7D)
Answer:
45 stickers left
Step-by-step explanation:
(-2,-3)
Mirror the point across the x-axis. If it is at (-2,3) then the reflection would be (-2, -3)
Answer:
<u>-6</u>
-7
Step-by-step explanation: (4,5) and (-3,-1)
- Y2 represents -1
- Y1 represents 5
- X2 represents -3
- X1 represents 4
<u>Y2 - Y1</u>
X2 - X1
<u>-1 - 5</u>
-3 - 4
<u>-6</u>
-7
Hope this helps you!!! :)
