Answer:
The right answer is the second option, 9,747.
Step-by-step explanation:
![EG^2 = DG*FG \\ EG^2 = 5*14 \\ EG = \sqrt{70}](https://tex.z-dn.net/?f=EG%5E2%20%3D%20DG%2AFG%20%5C%5C%20EG%5E2%20%3D%205%2A14%20%5C%5C%20EG%20%3D%20%5Csqrt%7B70%7D)
Now let's find DE (Pythagorean theorem).
![DE^2 = DG^2+EG^2\\ DE = \sqrt{25+70} \\ DE = \sqrt{95}](https://tex.z-dn.net/?f=DE%5E2%20%3D%20DG%5E2%2BEG%5E2%5C%5C%20DE%20%3D%20%5Csqrt%7B25%2B70%7D%20%5C%5C%20DE%20%3D%20%5Csqrt%7B95%7D)
![\sqrt{95} =9,7467... = 9,747](https://tex.z-dn.net/?f=%5Csqrt%7B95%7D%20%3D9%2C7467...%20%3D%209%2C747)
Given:
![\frac{475}{80}](https://tex.z-dn.net/?f=%5Cfrac%7B475%7D%7B80%7D)
Let's evaluate and find the quotient.
We have:
![\frac{475}{80}=5.9375](https://tex.z-dn.net/?f=%5Cfrac%7B475%7D%7B80%7D%3D5.9375)
SInce it is not a repeating decimal, we are asked to leave to answer as it is.
A repeating decimal is a decimal with digits or group of digits that repeats endlessly.
The decimal 5.937
ANSWER:
5.9375
Answer:
x ≈ 49.5°
Step-by-step explanation:
We use cos∅ to solve this:
cosx = 13/20
x = ![cos^{-1}(13/20)](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%2813%2F20%29)
x = 49.4584
You get 75,015.45 without rounding. once you round, you get 75,015.5