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pogonyaev
3 years ago
8

A=4, b=2,c=-1 find value of a-b+c

Mathematics
2 answers:
777dan777 [17]3 years ago
7 0

Answer:

1

Step-by-step explanation:

Substitute the value of the variable into the expression and simplify.

4-2-1=1

Elodia [21]3 years ago
3 0

Answer:

1

Step-by-step explanation:

a-b+c

=4-2+(-1)

=2-1

=1

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Natasha2012 [34]

Hello from MrBillDoesMath!

Answer:

x < -2

Discussion:

7 < 3 - 2x                       => Add 2x to both sides

7 + 2x < 3 - (2x - 2x)     =>  As 2x -2x = 0

7 + 2x < 3                      =>  Subtract  7 from both sides

(7-7) +  2x < 3 - 7           => As 7-7 = 0 and 3-7 = -4

2x < -4                           => Divide both sides by 2

x < -4./2 = -2

Thank you,

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7 0
3 years ago
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Drupady [299]

Answer:

22 feet

Step-by-step explanation:

33 * 2/3=22

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5 0
3 years ago
A doctor is measuring the mean systolic blood pressure of female students at a large college. Systolic blood pressure is known t
Nana76 [90]

Answer:

The correct option is (b).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times\frac{SD}{\sqrt{n}}

The confidence interval for population mean can be computed using either the <em>z</em>-interval or <em>t</em>-interval.

The <em>t</em>-interval is used if the following conditions are satisfied:

  • The population standard deviation is not known
  • The sample size is large enough
  • The population from which the sample is selected is normally distributed.

For computing a (1 - <em>α</em>)% confidence interval for population mean , it is necessary for the population to normally distributed if the sample selected is small, i.e.<em>n</em> < 30, because only then the sampling distribution of sample mean will be approximated by the normal distribution.

In this case the sample size is, <em>n</em> = 28 < 30.

Also it is provided that the systolic blood pressure is known to have a skewed distribution.

Since the sample is small and the population is not normally distributed, the  sampling distribution of sample mean will not be approximated by the normal distribution.

Thus, no conclusion can be drawn from the 90% confidence interval for the mean systolic blood pressure.

The correct option is (b).

5 0
2 years ago
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Helga [31]

Answer:

  The first question is A.

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4 0
2 years ago
A woman bought some large frames for ​$18 each and some small frames for ​$8 each at a closeout sale. If she bought 21 frames fo
IrinaVladis [17]

Answer:

<em> 8 large frames and 13 small frames</em>

Step-by-step explanation:

<u><em>Given:</em></u><em>
$18 each = large frames</em>

<em>$8 each = small frames</em>

<u><em>To Find:</em></u>

<em>⇒  Bought 21 frames for ​$​248, find how many of each type she bought</em>

<u><em>Solve:</em></u>

<em>1 Large frame costs = 18 $</em>

<em>Therefore, x large frames costs = 18x $</em>

<em>{where x is the number of large frames she bought}</em>

<em>1 Small frame costs = 8 $</em>

<em>Therefore, x Small frames costs = 8y $</em>

<em>{where y is the number of small frames she bought}</em>

<em>By the given condition :</em>

<em>18x + 8y = 248        {equation 1}</em>

<em>x + y = 21                 {equation 2}</em>

<em>Solve these equations simultaneously, from second equation we get :</em>

<em>x = 21- y</em>

<em>18⋅(21−y)+8y= 248</em>

<em>378 - 18y+8y = 248</em>

<em>-10y = -130</em>

<em>y = 13</em>

<em>Put y = 13 in eq x = 21- y</em>

<em>x = 21  - y</em>

<em>x = 21 - 13</em>

<em>x = 8</em>

<em>So the woman bought 8 large frames and 13 small frames.</em>

<em />

<u><em>~lenvy~</em></u>

5 0
2 years ago
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