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Nata [24]
2 years ago
11

A woman bought some large frames for ​$18 each and some small frames for ​$8 each at a closeout sale. If she bought 21 frames fo

r ​$​248, find how many of each type she bought.
Mathematics
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

<em> 8 large frames and 13 small frames</em>

Step-by-step explanation:

<u><em>Given:</em></u><em>
$18 each = large frames</em>

<em>$8 each = small frames</em>

<u><em>To Find:</em></u>

<em>⇒  Bought 21 frames for ​$​248, find how many of each type she bought</em>

<u><em>Solve:</em></u>

<em>1 Large frame costs = 18 $</em>

<em>Therefore, x large frames costs = 18x $</em>

<em>{where x is the number of large frames she bought}</em>

<em>1 Small frame costs = 8 $</em>

<em>Therefore, x Small frames costs = 8y $</em>

<em>{where y is the number of small frames she bought}</em>

<em>By the given condition :</em>

<em>18x + 8y = 248        {equation 1}</em>

<em>x + y = 21                 {equation 2}</em>

<em>Solve these equations simultaneously, from second equation we get :</em>

<em>x = 21- y</em>

<em>18⋅(21−y)+8y= 248</em>

<em>378 - 18y+8y = 248</em>

<em>-10y = -130</em>

<em>y = 13</em>

<em>Put y = 13 in eq x = 21- y</em>

<em>x = 21  - y</em>

<em>x = 21 - 13</em>

<em>x = 8</em>

<em>So the woman bought 8 large frames and 13 small frames.</em>

<em />

<u><em>~lenvy~</em></u>

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