Answer:
Replace text as you type.
Explanation:
Replace text as you type is the Autocorrect option that enables you to add and delete words that do not follow abbreviation rules. This tool is available under the PROOFING tab. For example, if you use a long phrase frequently, simply add it to the replace text as you type. For instance, if you type your address frequently, add 34 Willoughby Street, London, and abbreviate it to 34WS and it was replace it to the long phrase as you type 34WS.
Answer:
Call showValue (12)
Explanation:
The function is a block of the statement which performs the special task.
if you define the function, then you have to call that function.
Then, program control moves to the function and start to execute otherwise not execute the function.
the syntax for calling the function:
name(argument_1, argument_2,....);
we can put any number of arguments in the calling.
check the options one by one for finding the answer:
Call showValue( Integer): this is valid calling but it passes the variable, not the 12. this is not correct.
Call showValue( Integer 12): This is not valid calling, because it passes the data type as well which is incorrect.
Call showValue( Real): this is valid calling but it passes the variable, not the 12. this is not correct.
Call showValue (12): this valid calling and also pass the value 12.
Therefore, the correct answer is option b.
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer:
def corresponding_of_lists(lst1, lst2):
c = ""
corresponding_list = []
if (lst1 is None) or (lst2 is None):
return None
else:
for i in lst1:
for j in lst2:
c = "(" + str(i) + "," + str(j) + ")"
corresponding_list.append(c)
return corresponding_list
Explanation:
- Create a function called corresponding_of_lists that takes two lists as parameter
- Initialize an empty list to hold the corresponding values
- Check if any of the lists are null, if they are return None
- Otherwise, get the corresponding elements and put them into the corresponding_list
Return the corresponding_list
Answer:
Top to bottom Answer in order
#1 hardskills
#2 goal
#3 value
#4 soft skills
#5 on the job training
#6 self training
