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ehidna [41]
2 years ago
14

Help me plz with these problems

Mathematics
2 answers:
Shtirlitz [24]2 years ago
7 0
19. (X+5)-3
20. 2a
21.3b
22. 5y-5
23. 1/2n-15
Studentka2010 [4]2 years ago
3 0

19) 3 - (5+x)

20) 2a

21) 3b

22) 5y - 5

23) n/2 - 15

24) x/6

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Georgia [21]

Answer:

try acceleration

Step-by-step explanation:

8 0
2 years ago
Solve quadratic inequality x^2+4x≥0
klemol [59]

Answer:

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7 0
2 years ago
Perform the following division:
timofeeve [1]
(33/4) / (2/8)
when dividing with fractions, flip what u r dividing by, then multiply
33/4 * 8/2 = 66/2 = 33...hmm...not an answer choice

let me try something..
(3 3/4) / (2/8) =
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5 0
2 years ago
Read 2 more answers
If you answer this, i might give you 3 extra points (:
rodikova [14]
Jewelery maker has
24 jade beads
30 teak Beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
7 0
3 years ago
Read 2 more answers
Please answer fast!!!According to the Triangle Sum Theorem, which combinations of side lengths would make a possible triangle? C
saw5 [17]

Answer:

Is there a picture of it?

Step-by-step explanation:

7 0
2 years ago
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