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svetlana [45]
3 years ago
13

Please help me I don’t understand

Mathematics
1 answer:
Scilla [17]3 years ago
3 0
I think 8. Plug in -4 for x. 1/2-4^2
Using pemdas -4^2 is 16 and 1/2•16 is 8. If there were parenthesis around 1/2x then 1/2•-4 would be -2 and -2^2 is 4 but since there aren’t parentheses then 8
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The tables show the number of plants and the number of flowers. Which table represents a proportional relationship?
Usimov [2.4K]


 the last one because 7*3=21 14*3=42 and 21*3=63
4 0
3 years ago
Identify a3 of a sequence: 0.25, 0.5, 0.75, 1, 1.25, 1.5,....<br> a3=
wariber [46]

Answer:

0.75

Step-by-step explanation:

The given sequence is an AP , as the difference of all the terms is same

a_3 = 0.75

8 0
3 years ago
Find the missing side
enot [183]

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its E 21

Step-by-step explanation:

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Mindy conducts an experiment with three quarters. She counts the number of heads and tails for each flip of the three quarters.
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4 0
2 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
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