All categories

3 years ago

Please help me I don’t understand

Mathematics

1 answer:

Scilla [17]3 years ago

3 0

I think 8. Plug in -4 for x. 1/2-4^2
Using pemdas -4^2 is 16 and 1/2•16 is 8. If there were parenthesis around 1/2x then 1/2•-4 would be -2 and -2^2 is 4 but since there aren’t parentheses then 8

You might be interested in

Bruce's hourly wage increased from $12.00 to $13.00. What is the percent of increase?

kogti [31]

0.084 percent because that’s gone be equal to one dollar

8 0

3 years ago

Solve 4|x + 6| = 16

Galina-37 [17]

4 | x + 6 | = 16

Divide both sides by 4.

$\bf{\dfrac{4|x+6|}{4}=\dfrac{16}{4} }$

$\bf{|x+6|=4 }$

Absolute value is solved.

$\bf{|x+6|=4 }$

We know either x + 6 = 4 or x + 6 = -4.

x + 6 = 4 (Possibility 1)

x + 6 - 6 = 4 - 6 (Subtract 6 from both sides)

x=−2

x + 6 = -4 (Possibility 2)

x + 6 - 6 = -4 - 6 (Subtract 6 from both sides)

x=-10

Solution:

x=−2 or x=−10

$\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}$

3 0

2 years ago

Read 2 more answers

Sections of prefabricated wood are each 5 1/3 feet long. How long are 7 1/2 sections placed end to end?

ratelena [41]

Answer:

40 feet long

Step-by-step explanation:

5 1/3 * 7 1/2

16/3 * 15/2

240/6

40 feet long

7 0

3 years ago

Cai drove 189 miles in 7 hours. If he continued at the same rate, how far would he

bagirrra123 [75]

I think it is 324, I divided 189 by 7 which gave me 27 mph so I multiplied 27 by 12 which gave me 324 mph.

4 0

2 years ago

Findf '(3), where f(t) = u(t) · v(t), u(3) =1, 2, −2, u'(3) =8, 1, 4,andv(t) =t, t2, t3.

Reika [66]

Answer:

$f'(3)=100$

Step-by-step explanation:

Given:

$f(t)=u(t)\cdot v(t)\\u(3)=\left ( 1,2,-2 \right )\\u'\left ( 3 \right )=\left ( 8,1,4 \right )\\v(t)=\left ( t,t^{2},t^{3} \right )$

To find: $f'(3)$

Solution:

$v(t)=\left ( t,t^{2},t^{3} \right )$

At $t=3;$

$v(3)=(3,3^{2},3^{3} )=(3,9,27)$

Differentiate with respect to t

$v'(t)=\left ( 1,2t,3t^{2} \right )$

At $t=3;$

$v'(3)=\left ( 1,2(3),3(3)^{2} \right )=\left ( 1,6,27 \right )$

Using product rule, differentiate $f(t)=u(t)\cdot v(t)$ with respect to $t$

$f'(t)=u'(t)\cdot v(t)+u(t)\cdot v'(t)$

At $t=3;$

$f'(3)=u'(3)\cdot v(3)+u(3)\cdot v'(3)\\=\left ( 8,1,4 \right )\cdot \left ( 3,9,27 \right )+\left ( 1,2,-2 \right )\cdot \left ( 1,6,27 \right )\\=24+9+108+1+12-54\\=100$

7 0

4 years ago