Find the 9th term of the geometric sequence 8 , 32 , 128
1 answer:
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Answer:
see attachment
Step-by-step explanation:
The complex numbers in this table are the ones where a negative number is under the radical. The attachment has these circled.
Assuming you want the expression to be simplified.
We begin with the following:
Simplify the first part,
. That is 25. Now we have this:
Next, simplify
, which is 1/3, and get this:
The next part is
. Simplify the denominator, 
, which is 81. Simplify the numerator, which is 1/125. Then divide 1/125 by 81, which we will keep as a fraction for simplicity's sake, but simplify it to 
. Now we have:
Now simplify
, which is 0.2, or 1/5. Now we have:
Finally, simplify
. That is 1/27. We have:
Lastly, multiply them all together! Now we are done, with the product of:
That certainly did take a while to type in all the LaTex, so I really hope that helped!
Note- if anything isn't working with the LaTex, just tell me and I'll fix it! (:
We begin with the following:
Simplify the first part,
Next, simplify
The next part is
Now simplify
Finally, simplify
Lastly, multiply them all together! Now we are done, with the product of:
That certainly did take a while to type in all the LaTex, so I really hope that helped!
Note- if anything isn't working with the LaTex, just tell me and I'll fix it! (:
