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Lelu [443]
3 years ago
5

Find the 9th term of the geometric sequence 8 , 32 , 128

Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

the pattern seems to be to multiply by 4 so the answer would be 524,288

Step-by-step explanation:

8×4= 32×4= 128×4= 512×4= 2048×4= 8192×4= 32768×4= 131072×4= 524,288

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Find the unit price of 8 mugs that cost $38.32 total
kipiarov [429]

Answer:

4.79

Step-by-step explanation:

all together the total is 38.32

you want to find one so you do

38.32 ÷ 8 = $4.79

hope it helps!

4 0
3 years ago
Read 2 more answers
Can someone help find the area and perimeter of this??​
aalyn [17]

Answer:

area = 45 square meters

circumference = 33 meters

Step-by-step explanation:

lmk if you need explanation

7 0
2 years ago
PLS I NEED ASAP I WILL GIVE BRAINLIEST AND 30+ POINTS
Nadya [2.5K]

Question:

The diagram below shows the graph of a proportional relationship. The plotted point is (6,9) .

What is the unit rate of this graph? Be sure to simplify your answer.

Answer:

The unit rate of this graph is 1.5

Explanation:

The graph shows a proportional relationship and the plotted point is (6,9).

The unit rate of the graph can be determined by the formula,

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=m

Thus, from the graph, the coordinates are (0,0) and (6,9)

Substituting the coordinates in the formula, we have,

\frac{6-0}{9-0} =m

Subtracting, we get,

m=\frac{6}{9} =1.5

Thus, the unit rate of the graph is 1.5

7 0
3 years ago
Solve the system by elimination<br><br> 3x-2y=3<br> 15x-4y=-3
stiv31 [10]

Answer:

x=-1

y=-3

Step-by-step explanation:

3x-2y=3(1)

5.(1) <=> 15x-10y=15 (2)

15x-4y=-3 (3)

(2)-(3) <=> -6y=18

4 0
2 years ago
Select the correct answer from each drop-down menu.
ella [17]

Answer:

A non-equilateral rhombus.

Step-by-step explanation:

We can solve this graphically.

We start with square:

ABCD

with:

A = (11, - 7)

B = (9, - 4)

C = (11, - 1)

D = (13, - 4)

Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:

AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13

BC =  √( (11 - 9)^2 + (-1 -(-4))^2) = √13

CD =  √( (11 - 13)^2 + (-1 -(-4))^2)  = √13

DA =  √( (11 - 13)^2 + (-7 -(-4))^2) = √13

And we change C by C' = (11, 1)

In the image you can see the 5 points and the figure that they make:

The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.

5 0
2 years ago
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