Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:
Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000
1 Second prize $450
10 Third prize $25
No prize -$4
TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
Box volume = height * width * length. In this problem we want the length, so we solve the given equation for length:
720 in^3
length = -------------------- = 12 in
(15 in)(4 in)
The box is 12 inches long.
I tried my best with 1, 2, and 3
It is 8 to the one third power which is the same as the cube root of 8 which is 2. The answer is 2