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andre [41]
3 years ago
8

Simplify the expression. 11(3p + 5x) + 4x - x

Mathematics
2 answers:
nalin [4]3 years ago
8 0

Answer:

11(3p+5x)+4x-x  

Final result :

 33p + 58x

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (11 • (3p + 5x) +  4x) -  x

Step  2  :

Final result :

 33p + 58x

bixtya [17]3 years ago
5 0
The answer is:
33p+58x
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Which is the function represented by the table?
zheka24 [161]
The answer is A, you would plug in 3 for fx so therefore the answer would be A. Then to make sure plug in the other functions.:)
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3 years ago
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The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
sally gave her brother 3.95 in quarters and dimes. if the number of quarters is 6 more then the number of dimes, how many quarte
iragen [17]
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)

(2)->    q-d= 6
       q-d+d= 6+d
              q= 6+d...(2a)

(2a)-> (1)      0.25q+0.10d=3.95
              0.25(6+d)=0.10d= 3.95
           1.95+0.25d+0.10d= 3.95
                               0.35d= 3.95-1.5
                       0.35d/0.35= 2.45/0.35
                                      d= 7...(3)

(3)->(2)     q-d= 6
                 q-7= 6
                    q=6+7
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3 years ago
Driving to your friend's house, you travel at an average rate of 35 miles per hour. On your
Mamont248 [21]

Answer:

14 miles.

Step-by-step explanation:

Let the distance traveled from home to destination = x miles.

Speed while going to friend's house = 35 miles per hour.

Speed while coming back = 40 miles per hour.

Total Time taken for the journey = 45 minutes = 0.75 hours.

Let the time taken while going to friend's house = y hours.

Therefore, the time taken while going to friend's house = (0.75 - y) hours.

To find x and y, model the speeds of both the journeys.

Speed while going to friend's house = Distance/Time.

35 = x/y.

x = 35y (Equation 1).

Speed while coming back = Distance/Time.

40 = x/(0.75 - y).

x = 40(0.75 - y) (Equation 2).

Since x = x, therefore:

35y = 30 - 40y.

75y = 30.

y = 30/75.

y = 0.4 hours.

Put y = 0.4 hours in Equation 1:

x = 35y.

x = 35(0.4).

x = 14.

Therefore, the distance between my friend's house and my house is 14 miles!!!

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N76 [4]

Answer:

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Step-by-step explanation:

Given the following question:

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To estimate by the nearest thousand, we have to look at the thousand's place value and then look at the number next to it, to see if it's greater than five.

80767-37291

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37291

2 < 5

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81000-3700=44000

=44000

Hope this helps.

6 0
2 years ago
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