Answer:
The correct answer is:
$380 (D.)
Explanation:
The cost of production of a good or service is the amount used up or forfeited in the production of the good or service. In this scenario, from Ziva used 10 hours for farming and because she dedicated 10 hours, if she had been available for her consultancy service which paid her $25 per hour, she would have earned a total of $250 at the end of the 10 hours she used in farming. In addition, she also spend $130 on the seed that she used for planting, which is the direct cost of farming (production). Hence the total amount given up in the farming process will make up the total cost of farming, and this includes; the $250 given up for consultancy, and the $130 spent on seeds, hence, the total cost of production is;
= 250 + 130 = $380
Answer: $678,220
Explanation:
Given that,
Purchase Discounts = $ 11,000
Freight-in = $15,300
Purchases = $689,020
Beginning Inventory = $55,000
Ending Inventory = $45,600
Purchase Returns and Allowances = $15,100
Cost of goods purchased:
= Purchases + Freight in - Purchase discounts - Purchase returns and allowances
= $689,020 + $15,300 - $ 11,000 - $15,100
= $678,220
Answer: $50
Explanation:
We can use the Gordon Growth Model of Stock Valuation. The formula is thus,
P = D1 / r – g
D1 = the annual expected dividend of the next year
r = rate of return
g = the expected dividend growth rate (assumed to be constant)
There is no growth potential and dividends are expected to stay the same so no growth rate and D1 will be the same as D0.
Plugging that into the formula therefore will give us
P = D1/r
P= 4.5/0.09
= $50
Current Stock Price is $50.
There are several problems that make public goods necessary, but the primary one is that without access to certain public goods and services like parks and schools, poor people would have practically no chance at advancement.
Answer: V=7.43m/s
d =2.82m
Explanation:
a) For the first part, the initial velocity immediately after ejection, by using momentum conservation
before ejection, the momentum of the squid/water system is zero
there are no external forces acting on the system at the moment of ejection, so we can find the speed of the squid by noting
momentum before ejection = momentum after ejection
0 = M1U + M2V
0=-0.26 kg x 20 m/s + 0.7kg x V
where the speed of the water is taken as the negative sign, and V is the speed of the squid right after ejection, solving for V we get
V=7.43m/s
B. we use the equation vf^²=v0^²+2ad
where vf=final velocity = 0 since velocity is zero at motion's apex
v0=initial velocity = 7.43m/s
a = acceleration = -9.8m/s/s
d=height (to be found)
Therefore,
0=7.43^²+2(-9.8)d
Mathematically, it becomes
d=7.43^²/2(9.8)= 2.82m
d = 2.82m
